Specified Exception
There are different Errors (Exceptions) and you can handle the wrong error, for example:
123456789from math import sqrt a, b, c = 5, 4, 0 try: a += sqrt(b) / c except: print("The ValueError was raised!") print("a =", a)
There's a small issue with the provided Python code. The expected error from the sqrt(b) / c
expression is not a ValueError
but rather a ZeroDivisionError
. When the value of c
is set to 0, the expression sqrt(b) / c
will cause a division by zero error (ZeroDivisionError
).
We can use the following syntax to specify exceptions for code blocks:
except {error_type}:
# code block
Let's modify the code accordingly and catch the correct exception.
1234567891011from math import sqrt a, b, c = 5, 4, 0 try: a += sqrt(b) / c except ValueError: print("The ValueError was raised!") except ZeroDivisionError: print("The ZeroDivisionError was raised!") print("a =", a)
Now, we can distribute operations by certain exceptions!
Obrigado pelo seu feedback!
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Specified Exception
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There are different Errors (Exceptions) and you can handle the wrong error, for example:
123456789from math import sqrt a, b, c = 5, 4, 0 try: a += sqrt(b) / c except: print("The ValueError was raised!") print("a =", a)
There's a small issue with the provided Python code. The expected error from the sqrt(b) / c
expression is not a ValueError
but rather a ZeroDivisionError
. When the value of c
is set to 0, the expression sqrt(b) / c
will cause a division by zero error (ZeroDivisionError
).
We can use the following syntax to specify exceptions for code blocks:
except {error_type}:
# code block
Let's modify the code accordingly and catch the correct exception.
1234567891011from math import sqrt a, b, c = 5, 4, 0 try: a += sqrt(b) / c except ValueError: print("The ValueError was raised!") except ZeroDivisionError: print("The ZeroDivisionError was raised!") print("a =", a)
Now, we can distribute operations by certain exceptions!
Obrigado pelo seu feedback!