Building a Linked List
Let's write a simple function to create a node. This function should:
- As an argument, take a number of type int, which will be stored in the node in the data field;
- Create a pointer to a dynamically allocated memory area (taking into account the size of the node);
- Check the success of memory allocation for the node;
- Put the required value (function argument) into the data field;
- The next pointer must be NULL, since the function creates only one node;
- The function must return a pointer to the memory area where value is stored.
The AddNewNode() function takes a pointer to a pointer, because it can change the value of the pointer to the first (head) node of the list, as well as the value that will be stored in the new node:
void AddNewNode(struct Node** head, int value)
{
...
}
If the list is empty (*head == NULL), we simply update the pointer to the head of the list (*head) to point to the new node (newNode), in which case newNode will become the first node (head node). In the case of a non-empty list, we use a loop to look for the last node.
The current node plays the role of a buffer node, with its help we can iterate through the list and find a node that points to nowhere (*next == NULL).
Note
The last node in the list will have a next pointer equal to NULL.
struct Node* current = *head;
while (current->next != NULL)
{
…
}
After all, you need to make the new node newNode
the last node, which means current->next
must be equal to newNode
. Now newNode is the last node in the list.
As a task, you need to figure out and add a function for adding new nodes to existing nodes.
Swipe to start coding
-
Create a new node
newNode
, which will store the data value; -
Specify the condition under which the list will be considered empty;
-
Specify what
current->next
will be equal to after the loop completes.
Рішення
Дякуємо за ваш відгук!
single
Запитати АІ
Запитати АІ
Запитайте про що завгодно або спробуйте одне із запропонованих запитань, щоб почати наш чат
Awesome!
Completion rate improved to 4.17
Building a Linked List
Свайпніть щоб показати меню
Let's write a simple function to create a node. This function should:
- As an argument, take a number of type int, which will be stored in the node in the data field;
- Create a pointer to a dynamically allocated memory area (taking into account the size of the node);
- Check the success of memory allocation for the node;
- Put the required value (function argument) into the data field;
- The next pointer must be NULL, since the function creates only one node;
- The function must return a pointer to the memory area where value is stored.
The AddNewNode() function takes a pointer to a pointer, because it can change the value of the pointer to the first (head) node of the list, as well as the value that will be stored in the new node:
void AddNewNode(struct Node** head, int value)
{
...
}
If the list is empty (*head == NULL), we simply update the pointer to the head of the list (*head) to point to the new node (newNode), in which case newNode will become the first node (head node). In the case of a non-empty list, we use a loop to look for the last node.
The current node plays the role of a buffer node, with its help we can iterate through the list and find a node that points to nowhere (*next == NULL).
Note
The last node in the list will have a next pointer equal to NULL.
struct Node* current = *head;
while (current->next != NULL)
{
…
}
After all, you need to make the new node newNode
the last node, which means current->next
must be equal to newNode
. Now newNode is the last node in the list.
As a task, you need to figure out and add a function for adding new nodes to existing nodes.
Swipe to start coding
-
Create a new node
newNode
, which will store the data value; -
Specify the condition under which the list will be considered empty;
-
Specify what
current->next
will be equal to after the loop completes.
Рішення
Дякуємо за ваш відгук!
Awesome!
Completion rate improved to 4.17single