Завдання: Break та Continue
There is a for loop without a default ending condition.
Inside the loop, skip all the even iterations and in case of odd iterations increment the value of oddNumbers. Stop the loop as soon as the value of oddNumbers equals 27. Use break and continue statements for this purpose.
main.cs
12345678910111213141516171819202122232425using System; namespace ConsoleApp { internal class Program { static void Main(string[] args) { int oddNumbers = 0; for (int i = 0; ; i++) { if (___) { ___ } ___++; Console.WriteLine(i); if (___) { ___ } } } } }
A number x is even if it satisfies the condition x % 2 == 0.
main.cs
12345678910111213141516171819202122232425using System; namespace ConsoleApp { class Program { static void Main(string[] args) { int oddNumbers = 0; for (int i = 0; ; i++) { if (i % 2 == 0) { continue; } oddNumbers++; Console.WriteLine(i); if (oddNumbers == 27) { break; } } } } }
Дякуємо за ваш відгук!
Запитати АІ
Запитати АІ
Запитайте про що завгодно або спробуйте одне із запропонованих запитань, щоб почати наш чат
Awesome!
Completion rate improved to 1.59
Завдання: Break та Continue
Свайпніть щоб показати меню
There is a for loop without a default ending condition.
Inside the loop, skip all the even iterations and in case of odd iterations increment the value of oddNumbers. Stop the loop as soon as the value of oddNumbers equals 27. Use break and continue statements for this purpose.
main.cs
12345678910111213141516171819202122232425using System; namespace ConsoleApp { internal class Program { static void Main(string[] args) { int oddNumbers = 0; for (int i = 0; ; i++) { if (___) { ___ } ___++; Console.WriteLine(i); if (___) { ___ } } } } }
A number x is even if it satisfies the condition x % 2 == 0.
main.cs
12345678910111213141516171819202122232425using System; namespace ConsoleApp { class Program { static void Main(string[] args) { int oddNumbers = 0; for (int i = 0; ; i++) { if (i % 2 == 0) { continue; } oddNumbers++; Console.WriteLine(i); if (oddNumbers == 27) { break; } } } } }
Дякуємо за ваш відгук!