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Dealing with Dates and Times in Python
Dealing with Dates and Times in Python
Date Formats
There are several date formats applied across the world. Also sometimes we want to convert a date into some readable or presentable format. For example, we can rewrite the same date in multiple ways: "01.11.2021", "11/01/2021", "11 Nov, 2021", "2021-11-01", and so on... How can we transform dates so they still will be interpreted by Python?
So, how can we transform the date object into another format? At first, we need to load datetime class from the datetime library within a new line (yes, sounds tautological). Then, you need to apply .strftime() method of datetime class (datetime.strftime()) with a date as the first argument, and pattern as the second. There where the complexity starts. A pattern - is a string, that can be built using the next format codes (the list is not full):
| Format code | Meaning | Example |
%d | Day of the month as a zero-padded decimal number | 01, 02, ..., 30, 31 |
%m | Month as a zero-padded decimal number | 01, 02, ..., 11, 12 |
%y | Year without century as a zero-padded decimal number | 00, 01, 02, ..., 98, 99 |
%Y | Year with century as a decimal number | 0001, 0002, 1999, 2000, 2001, ... |
%b | Month as locale’s abbreviated name | Jan, Feb, ..., Nov, Dec |
%B | Month as locale’s full name | January, February, ..., November, December |
%a | Weekday as locale’s abbreviated name | Sun, Mon, ..., Fri, Sat |
%A | Weekday as locale’s full name | Sunday, Monday, ..., Friday, Saturday |
Let's build some examples. For example, we can create a date object representing the 28th of June, 2012. And let's transform it into two forms: "June 28, 2012" and "2012/06/28".
Consider the first format: there we need full month name (B), day of the month (%d) and 4-digit year (%Y). So the pattern will look like "%B %d, %Y".
In a similar way the second pattern can be built: 4-digit year (%Y), month as a zero-padded decimal number (%m), and day of the month (%d). In this case, the pattern will look like "%Y/%m/%d".
# Load classes from library from datetime import date from datetime import datetime # Create date object some_date = date(2012, 6, 28) # Format date into the first format print("Transformed into the first format date:", datetime.strftime(some_date, "%B %d, %Y")) # Format date into the first format print("Transformed into the second format date:", datetime.strftime(some_date, "%Y/%m/%d"))
Tarefa
Given date object (1998-03-11) assigned to variable day. Using .strftime() method format day to format: "11.03.98" and save the result in day_formatted variable.
Tarefa
Given date object (1998-03-11) assigned to variable day. Using .strftime() method format day to format: "11.03.98" and save the result in day_formatted variable.
Mude para o desktop para praticar no mundo realContinue de onde você está usando uma das opções abaixoTudo estava claro?
Date Formats
There are several date formats applied across the world. Also sometimes we want to convert a date into some readable or presentable format. For example, we can rewrite the same date in multiple ways: "01.11.2021", "11/01/2021", "11 Nov, 2021", "2021-11-01", and so on... How can we transform dates so they still will be interpreted by Python?
So, how can we transform the date object into another format? At first, we need to load datetime class from the datetime library within a new line (yes, sounds tautological). Then, you need to apply .strftime() method of datetime class (datetime.strftime()) with a date as the first argument, and pattern as the second. There where the complexity starts. A pattern - is a string, that can be built using the next format codes (the list is not full):
| Format code | Meaning | Example |
%d | Day of the month as a zero-padded decimal number | 01, 02, ..., 30, 31 |
%m | Month as a zero-padded decimal number | 01, 02, ..., 11, 12 |
%y | Year without century as a zero-padded decimal number | 00, 01, 02, ..., 98, 99 |
%Y | Year with century as a decimal number | 0001, 0002, 1999, 2000, 2001, ... |
%b | Month as locale’s abbreviated name | Jan, Feb, ..., Nov, Dec |
%B | Month as locale’s full name | January, February, ..., November, December |
%a | Weekday as locale’s abbreviated name | Sun, Mon, ..., Fri, Sat |
%A | Weekday as locale’s full name | Sunday, Monday, ..., Friday, Saturday |
Let's build some examples. For example, we can create a date object representing the 28th of June, 2012. And let's transform it into two forms: "June 28, 2012" and "2012/06/28".
Consider the first format: there we need full month name (B), day of the month (%d) and 4-digit year (%Y). So the pattern will look like "%B %d, %Y".
In a similar way the second pattern can be built: 4-digit year (%Y), month as a zero-padded decimal number (%m), and day of the month (%d). In this case, the pattern will look like "%Y/%m/%d".
# Load classes from library from datetime import date from datetime import datetime # Create date object some_date = date(2012, 6, 28) # Format date into the first format print("Transformed into the first format date:", datetime.strftime(some_date, "%B %d, %Y")) # Format date into the first format print("Transformed into the second format date:", datetime.strftime(some_date, "%Y/%m/%d"))
Tarefa
Given date object (1998-03-11) assigned to variable day. Using .strftime() method format day to format: "11.03.98" and save the result in day_formatted variable.
Tarefa
Given date object (1998-03-11) assigned to variable day. Using .strftime() method format day to format: "11.03.98" and save the result in day_formatted variable.
Mude para o desktop para praticar no mundo realContinue de onde você está usando uma das opções abaixoTudo estava claro?
Date Formats
There are several date formats applied across the world. Also sometimes we want to convert a date into some readable or presentable format. For example, we can rewrite the same date in multiple ways: "01.11.2021", "11/01/2021", "11 Nov, 2021", "2021-11-01", and so on... How can we transform dates so they still will be interpreted by Python?
So, how can we transform the date object into another format? At first, we need to load datetime class from the datetime library within a new line (yes, sounds tautological). Then, you need to apply .strftime() method of datetime class (datetime.strftime()) with a date as the first argument, and pattern as the second. There where the complexity starts. A pattern - is a string, that can be built using the next format codes (the list is not full):
| Format code | Meaning | Example |
%d | Day of the month as a zero-padded decimal number | 01, 02, ..., 30, 31 |
%m | Month as a zero-padded decimal number | 01, 02, ..., 11, 12 |
%y | Year without century as a zero-padded decimal number | 00, 01, 02, ..., 98, 99 |
%Y | Year with century as a decimal number | 0001, 0002, 1999, 2000, 2001, ... |
%b | Month as locale’s abbreviated name | Jan, Feb, ..., Nov, Dec |
%B | Month as locale’s full name | January, February, ..., November, December |
%a | Weekday as locale’s abbreviated name | Sun, Mon, ..., Fri, Sat |
%A | Weekday as locale’s full name | Sunday, Monday, ..., Friday, Saturday |
Let's build some examples. For example, we can create a date object representing the 28th of June, 2012. And let's transform it into two forms: "June 28, 2012" and "2012/06/28".
Consider the first format: there we need full month name (B), day of the month (%d) and 4-digit year (%Y). So the pattern will look like "%B %d, %Y".
In a similar way the second pattern can be built: 4-digit year (%Y), month as a zero-padded decimal number (%m), and day of the month (%d). In this case, the pattern will look like "%Y/%m/%d".
# Load classes from library from datetime import date from datetime import datetime # Create date object some_date = date(2012, 6, 28) # Format date into the first format print("Transformed into the first format date:", datetime.strftime(some_date, "%B %d, %Y")) # Format date into the first format print("Transformed into the second format date:", datetime.strftime(some_date, "%Y/%m/%d"))
Tarefa
Given date object (1998-03-11) assigned to variable day. Using .strftime() method format day to format: "11.03.98" and save the result in day_formatted variable.
Tarefa
Given date object (1998-03-11) assigned to variable day. Using .strftime() method format day to format: "11.03.98" and save the result in day_formatted variable.
Mude para o desktop para praticar no mundo realContinue de onde você está usando uma das opções abaixoTudo estava claro?
There are several date formats applied across the world. Also sometimes we want to convert a date into some readable or presentable format. For example, we can rewrite the same date in multiple ways: "01.11.2021", "11/01/2021", "11 Nov, 2021", "2021-11-01", and so on... How can we transform dates so they still will be interpreted by Python?
So, how can we transform the date object into another format? At first, we need to load datetime class from the datetime library within a new line (yes, sounds tautological). Then, you need to apply .strftime() method of datetime class (datetime.strftime()) with a date as the first argument, and pattern as the second. There where the complexity starts. A pattern - is a string, that can be built using the next format codes (the list is not full):
| Format code | Meaning | Example |
%d | Day of the month as a zero-padded decimal number | 01, 02, ..., 30, 31 |
%m | Month as a zero-padded decimal number | 01, 02, ..., 11, 12 |
%y | Year without century as a zero-padded decimal number | 00, 01, 02, ..., 98, 99 |
%Y | Year with century as a decimal number | 0001, 0002, 1999, 2000, 2001, ... |
%b | Month as locale’s abbreviated name | Jan, Feb, ..., Nov, Dec |
%B | Month as locale’s full name | January, February, ..., November, December |
%a | Weekday as locale’s abbreviated name | Sun, Mon, ..., Fri, Sat |
%A | Weekday as locale’s full name | Sunday, Monday, ..., Friday, Saturday |
Let's build some examples. For example, we can create a date object representing the 28th of June, 2012. And let's transform it into two forms: "June 28, 2012" and "2012/06/28".
Consider the first format: there we need full month name (B), day of the month (%d) and 4-digit year (%Y). So the pattern will look like "%B %d, %Y".
In a similar way the second pattern can be built: 4-digit year (%Y), month as a zero-padded decimal number (%m), and day of the month (%d). In this case, the pattern will look like "%Y/%m/%d".
# Load classes from library from datetime import date from datetime import datetime # Create date object some_date = date(2012, 6, 28) # Format date into the first format print("Transformed into the first format date:", datetime.strftime(some_date, "%B %d, %Y")) # Format date into the first format print("Transformed into the second format date:", datetime.strftime(some_date, "%Y/%m/%d"))
Tarefa
Given date object (1998-03-11) assigned to variable day. Using .strftime() method format day to format: "11.03.98" and save the result in day_formatted variable.
Mude para o desktop para praticar no mundo realContinue de onde você está usando uma das opções abaixoMude para o desktop para praticar no mundo realContinue de onde você está usando uma das opções abaixo