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Fundamental Data Structures in Java

bookChallenge: Implementing BrowserHistory

Tarefa

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In this task, you need to complete the BrowserHistory class by filling in the missing parts. The goal is to implement a basic browser history system using two stacks: one for back navigation (backStack) and one for forward navigation (forwardStack).

You will handle visiting new pages, moving backward and forward through history, and keeping track of the current page. Use Deque.

  1. In the visit(String url) method:

    • Add the currentPage to the backStack.
    • Update currentPage to the new url.
    • Clear the forwardStack to reset forward history.
  2. In the back(int steps) method:

    • The loop should continue while steps > 0 and backStack is not empty.
    • Push the currentPage onto the forwardStack.
    • Pop the last page from the backStack and assign it to currentPage.
    • After moving backward, return the currentPage.
  3. In the forward(int steps) method:

    • The loop should continue while steps > 0 and forwardStack is not empty.
    • Push the currentPage onto the backStack.
    • Pop the last page from the forwardStack and assign it to currentPage.
    • After moving forward, return the currentPage.
  4. In the getCurrentPage() method:

    • Simply return the currentPage.

Solução

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Seção 1. Capítulo 12
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bookChallenge: Implementing BrowserHistory

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Tarefa

Swipe to start coding

In this task, you need to complete the BrowserHistory class by filling in the missing parts. The goal is to implement a basic browser history system using two stacks: one for back navigation (backStack) and one for forward navigation (forwardStack).

You will handle visiting new pages, moving backward and forward through history, and keeping track of the current page. Use Deque.

  1. In the visit(String url) method:

    • Add the currentPage to the backStack.
    • Update currentPage to the new url.
    • Clear the forwardStack to reset forward history.
  2. In the back(int steps) method:

    • The loop should continue while steps > 0 and backStack is not empty.
    • Push the currentPage onto the forwardStack.
    • Pop the last page from the backStack and assign it to currentPage.
    • After moving backward, return the currentPage.
  3. In the forward(int steps) method:

    • The loop should continue while steps > 0 and forwardStack is not empty.
    • Push the currentPage onto the backStack.
    • Pop the last page from the forwardStack and assign it to currentPage.
    • After moving forward, return the currentPage.
  4. In the getCurrentPage() method:

    • Simply return the currentPage.

Solução

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Tudo estava claro?

Como podemos melhorá-lo?

Obrigado pelo seu feedback!

Seção 1. Capítulo 12
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single

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