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Aprenda Deeping into Pointers | References & Pointers
C++ Intermediate | Mobile-Friendly
course content

Conteúdo do Curso

C++ Intermediate | Mobile-Friendly

C++ Intermediate | Mobile-Friendly

1. Data Types and Arrays
2. References & Pointers
3. Dynamic Memory
4. Functions

book
Deeping into Pointers

Let’s return to the previous code:

python

Here the variable pb is a pointer. It contains the address to the variable b. Use the pointer without an asterisk to output the address the pointer contains and with an asterisk to get the value of the variable by address:

12
cout << pb << endl; // address of the variable b cout << *pb << endl; // the value of the b
copy

The pointer always points to the address of the declared variable, and if the value of the variable changes, the address doesn’t:

1234567
int b = 2; int *pb = &b; cout << *pb << endl; b = 1; cout << *pb << endl
copy

1. Which of the following statements is true?

2. Output the address of x and then the value of x using pointers.

question mark

Which of the following statements is true?

Select the correct answer

question-icon

Output the address of x and then the value of x using pointers.

int x = 2;
int *px = &x;

cout <<
<< endl;
cout <<
;

Clique ou arraste solte itens e preencha os espaços

Tudo estava claro?

Como podemos melhorá-lo?

Obrigado pelo seu feedback!

Seção 2. Capítulo 2

Pergunte à IA

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Pergunte o que quiser ou experimente uma das perguntas sugeridas para iniciar nosso bate-papo

course content

Conteúdo do Curso

C++ Intermediate | Mobile-Friendly

C++ Intermediate | Mobile-Friendly

1. Data Types and Arrays
2. References & Pointers
3. Dynamic Memory
4. Functions

book
Deeping into Pointers

Let’s return to the previous code:

python

Here the variable pb is a pointer. It contains the address to the variable b. Use the pointer without an asterisk to output the address the pointer contains and with an asterisk to get the value of the variable by address:

12
cout << pb << endl; // address of the variable b cout << *pb << endl; // the value of the b
copy

The pointer always points to the address of the declared variable, and if the value of the variable changes, the address doesn’t:

1234567
int b = 2; int *pb = &b; cout << *pb << endl; b = 1; cout << *pb << endl
copy

1. Which of the following statements is true?

2. Output the address of x and then the value of x using pointers.

question mark

Which of the following statements is true?

Select the correct answer

question-icon

Output the address of x and then the value of x using pointers.

int x = 2;
int *px = &x;

cout <<
<< endl;
cout <<
;

Clique ou arraste solte itens e preencha os espaços

Tudo estava claro?

Como podemos melhorá-lo?

Obrigado pelo seu feedback!

Seção 2. Capítulo 2
Sentimos muito que algo saiu errado. O que aconteceu?
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