Leer Chaining Multiple Decorators | Advanced Decorator Techniques


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def bold_decorator(func):
    def wrapper(*args, **kwargs):
        return "<b>" + func(*args, **kwargs) + "</b>"
    return wrapper

def italic_decorator(func):
    def wrapper(*args, **kwargs):
        return "<i>" + func(*args, **kwargs) + "</i>"
    return wrapper

@bold_decorator
@italic_decorator
def greet():
    return "Hello!"

print(greet())
# Output: <b><i>Hello!</i></b>

When you chain multiple decorators on a single function, Python applies them from the closest decorator to the function outward, but executes them in the reverse order. In the provided example, @italic_decorator is applied to greet first, then @bold_decorator wraps the result. This means that when you call greet(), the call first goes through bold_decorator, which then calls the version of greet that has already been wrapped by italic_decorator. As a result, the output is enclosed first in ..., then in ..., producing Hello!. Understanding this order is crucial when combining multiple decorators, as the sequence can affect the final behavior and output of your function.

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              1234567891011121314151617
            
def bold_decorator(func):
    def wrapper(*args, **kwargs):
        return "<b>" + func(*args, **kwargs) + "</b>"
    return wrapper

def italic_decorator(func):
    def wrapper(*args, **kwargs):
        return "<i>" + func(*args, **kwargs) + "</i>"
    return wrapper

@bold_decorator
@italic_decorator
def greet():
    return "Hello!"

print(greet())
# Output: <b><i>Hello!</i></b>

Was alles duidelijk?

Bedankt voor je feedback!

Sectie 2. Hoofdstuk 2