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Leer Specified Exception | Handling Structure
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Error Handling in Python

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There are different Errors (Exceptions) and you can handle the wrong error, for example:

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from math import sqrt a, b, c = 5, 4, 0 try: a += sqrt(b) / c except: print("The ValueError was raised!") print("a =", a)
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There's a small issue with the provided Python code. The expected error from the sqrt(b) / c expression is not a ValueError but rather a ZeroDivisionError. When the value of c is set to 0, the expression sqrt(b) / c will cause a division by zero error (ZeroDivisionError).

We can use the following syntax to specify exceptions for code blocks:

except {error_type}:
    # code block

Let's modify the code accordingly and catch the correct exception.

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from math import sqrt a, b, c = 5, 4, 0 try: a += sqrt(b) / c except ValueError: print("The ValueError was raised!") except ZeroDivisionError: print("The ZeroDivisionError was raised!") print("a =", a)
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Now, we can distribute operations by certain exceptions!

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