Notice: This page requires JavaScript to function properly.
Please enable JavaScript in your browser settings or update your browser.
Leer Challenge: Table Join | Joining Tables
Intermediate SQL
course content

Cursusinhoud

Intermediate SQL

Intermediate SQL

1. Grouping
2. Nested Subqueries
3. Joining Tables
4. DDL and DML in SQL

book
Challenge: Table Join

In this task, you'll need to use a different type of JOIN, or you can use the same one you used in the previous chapter, as long as you get the correct result.

Taak

Swipe to start coding

Write a query to retrieve a list of all students and the courses they are enrolled in, including students who are not enrolled in any course.

Use an appropriate type of JOIN and use the columns in the following order:

bash

As you can see, there are no aliases here, so do not use them to ensure the task is correctly evaluated.

Brief Instructions

  • Retrieve the necessary columns from the courses table.
  • Use a RIGHT JOIN to join the enrollments table.
  • The common column for both tables is enrollments.course_id = courses.course_id.

Oplossing

Switch to desktopSchakel over naar desktop voor praktijkervaringGa verder vanaf waar je bent met een van de onderstaande opties
Was alles duidelijk?

Hoe kunnen we het verbeteren?

Bedankt voor je feedback!

Sectie 3. Hoofdstuk 6
toggle bottom row

book
Challenge: Table Join

In this task, you'll need to use a different type of JOIN, or you can use the same one you used in the previous chapter, as long as you get the correct result.

Taak

Swipe to start coding

Write a query to retrieve a list of all students and the courses they are enrolled in, including students who are not enrolled in any course.

Use an appropriate type of JOIN and use the columns in the following order:

bash

As you can see, there are no aliases here, so do not use them to ensure the task is correctly evaluated.

Brief Instructions

  • Retrieve the necessary columns from the courses table.
  • Use a RIGHT JOIN to join the enrollments table.
  • The common column for both tables is enrollments.course_id = courses.course_id.

Oplossing

Switch to desktopSchakel over naar desktop voor praktijkervaringGa verder vanaf waar je bent met een van de onderstaande opties
Was alles duidelijk?

Hoe kunnen we het verbeteren?

Bedankt voor je feedback!

Sectie 3. Hoofdstuk 6
Switch to desktopSchakel over naar desktop voor praktijkervaringGa verder vanaf waar je bent met een van de onderstaande opties
Onze excuses dat er iets mis is gegaan. Wat is er gebeurd?
some-alt