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Understanding the Midrange in an Array

The midrange is a simple statistical concept that represents the average of the smallest and largest values in a set of numbers. In the context of arrays in C#, you can think of the midrange as the value exactly halfway between the minimum and maximum elements in the array.

How to Calculate the Midrange:

Identify the smallest value in the array (also called the minimum);
Identify the largest value in the array (also called the maximum);
Add these two values together;
Divide the sum by 2 to find the average.

Formula:

Midrange = (Minimum Value + Maximum Value) / 2

Example:

Suppose you have the following array:

int[] numbers = { 3, 7, 2, 9, 4 };

The smallest value is 2.
The largest value is 9.

So, the midrange is:

Midrange = (2 + 9) / 2 = 11 / 2 = 5.5

This value (5.5) represents the midpoint between the smallest and largest numbers in the array.

Use indexing to access the smallest and the largest elements of the array.

main.cs


              1234567891011121314151617
            
using System;

namespace ConsoleApp
{
    internal class Program
    {
        static void Main(string[] args)
        {
			int[] numbers = { 5, 9, 27, 17, 19, 21, 0, -7, 10 };

            int sum = ___;
            int mean = ___;

            Console.WriteLine(mean);
        }
    }
}

The sum variable should contain the sum of the two values.
Figure out the index of the smallest and the largest elements of the numbers array and access those elements via indexing (numbers[index]), then store their sum in the sum variable.
The mean will be the sum divided by 2.

main.cs


              1234567891011121314151617
            
using System;

namespace ConsoleApp
{
    internal class Program
    {
        static void Main(string[] args)
        {
            int[] numbers = { 5, 9, 27, 17, 19, 21, 0, -7, 10 };

            int sum = numbers[2] + numbers[7];
            int mean = sum / 2;

            Console.WriteLine(mean);
        }
    }
}

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Suggested prompts:

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Understanding the Midrange in an Array

How to Calculate the Midrange:

Identify the smallest value in the array (also called the minimum);
Identify the largest value in the array (also called the maximum);
Add these two values together;
Divide the sum by 2 to find the average.

Formula:

Midrange = (Minimum Value + Maximum Value) / 2

Example:

Suppose you have the following array:

int[] numbers = { 3, 7, 2, 9, 4 };

The smallest value is 2.
The largest value is 9.

So, the midrange is:

Midrange = (2 + 9) / 2 = 11 / 2 = 5.5

This value (5.5) represents the midpoint between the smallest and largest numbers in the array.

Use indexing to access the smallest and the largest elements of the array.

main.cs


              1234567891011121314151617
            
using System;

namespace ConsoleApp
{
    internal class Program
    {
        static void Main(string[] args)
        {
			int[] numbers = { 5, 9, 27, 17, 19, 21, 0, -7, 10 };

            int sum = ___;
            int mean = ___;

            Console.WriteLine(mean);
        }
    }
}

The sum variable should contain the sum of the two values.
Figure out the index of the smallest and the largest elements of the numbers array and access those elements via indexing (numbers[index]), then store their sum in the sum variable.
The mean will be the sum divided by 2.

main.cs


              1234567891011121314151617
            
using System;

namespace ConsoleApp
{
    internal class Program
    {
        static void Main(string[] args)
        {
            int[] numbers = { 5, 9, 27, 17, 19, 21, 0, -7, 10 };

            int sum = numbers[2] + numbers[7];
            int mean = sum / 2;

            Console.WriteLine(mean);
        }
    }
}

Was alles duidelijk?

Bedankt voor je feedback!

Sectie 5. Hoofdstuk 4