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Impara Immutabilità delle Stringhe | Stringhe
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Tipi di Dati in Python

bookImmutabilità delle Stringhe

In Python, strings are immutable: once created, the characters they contain cannot be changed in place. Any "modification" you do actually creates a new string. This matters for correctness (no accidental in-place edits) and for performance (how you build larger strings).

No In-Place Edits

You can read characters by index, but you cannot assign to them.

123456
s = "hello" t = "H" + s[1:] # Creates a new string: "Hello" print(t) s[0] = "H" # TypeError: strings don't support item assignment
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Most string methods return a new string and leave the original unchanged.

12345678
# Cleaning up user input from a registration form user_name = " Alice " user_name.strip() # returns "Alice", but the variable still has spaces print(user_name) # " Alice " user_name = user_name.strip() # assign the cleaned value back print(user_name) # "Alice" → cleaned and ready to store
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Chaining is fine, but remember you're getting a new object each step.

123456
# Normalizing a user's chat message before saving it user_message = " hello\n" clean_message = user_message.strip().upper() print(user_message) # original remains " hello\n" print(clean_message) # "HELLO" → cleaned and ready for processing
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"Modifying" By Creating a New String

Use slicing, replace, or concatenation to produce a new value.

1234567
s = "data" s = s.replace("t", "T") # "daTa" print(s) s = s[:1] + "A" + s[2:] # "dATa" print(s)
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Efficient Building

Repeated + in large loops can be slow (many intermediate strings). A common pattern is to collect pieces and join once:

1234
# Combining message parts received from a device response_parts = ["Status:", " ", "200", "\n", "Success"] response_message = "".join(response_parts) # "Status: 200\nSuccess" print(response_message)
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Note
Note

You'll learn more joining/formatting patterns in the next chapter.

1. Which line attempts to modify a string in place and will raise an error?

2. What will the code output?

3. You need to assemble a long string from many small pieces. What's recommended?

question mark

Which line attempts to modify a string in place and will raise an error?

Select the correct answer

question mark

What will the code output?

Select the correct answer

question mark

You need to assemble a long string from many small pieces. What's recommended?

Select the correct answer

Tutto è chiaro?

Come possiamo migliorarlo?

Grazie per i tuoi commenti!

Sezione 3. Capitolo 4

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Suggested prompts:

Can you explain why string immutability is important in Python?

How can I efficiently modify or build large strings in Python?

What are some common mistakes to avoid when working with immutable strings?

bookImmutabilità delle Stringhe

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In Python, strings are immutable: once created, the characters they contain cannot be changed in place. Any "modification" you do actually creates a new string. This matters for correctness (no accidental in-place edits) and for performance (how you build larger strings).

No In-Place Edits

You can read characters by index, but you cannot assign to them.

123456
s = "hello" t = "H" + s[1:] # Creates a new string: "Hello" print(t) s[0] = "H" # TypeError: strings don't support item assignment
copy

Most string methods return a new string and leave the original unchanged.

12345678
# Cleaning up user input from a registration form user_name = " Alice " user_name.strip() # returns "Alice", but the variable still has spaces print(user_name) # " Alice " user_name = user_name.strip() # assign the cleaned value back print(user_name) # "Alice" → cleaned and ready to store
copy

Chaining is fine, but remember you're getting a new object each step.

123456
# Normalizing a user's chat message before saving it user_message = " hello\n" clean_message = user_message.strip().upper() print(user_message) # original remains " hello\n" print(clean_message) # "HELLO" → cleaned and ready for processing
copy

"Modifying" By Creating a New String

Use slicing, replace, or concatenation to produce a new value.

1234567
s = "data" s = s.replace("t", "T") # "daTa" print(s) s = s[:1] + "A" + s[2:] # "dATa" print(s)
copy

Efficient Building

Repeated + in large loops can be slow (many intermediate strings). A common pattern is to collect pieces and join once:

1234
# Combining message parts received from a device response_parts = ["Status:", " ", "200", "\n", "Success"] response_message = "".join(response_parts) # "Status: 200\nSuccess" print(response_message)
copy
Note
Note

You'll learn more joining/formatting patterns in the next chapter.

1. Which line attempts to modify a string in place and will raise an error?

2. What will the code output?

3. You need to assemble a long string from many small pieces. What's recommended?

question mark

Which line attempts to modify a string in place and will raise an error?

Select the correct answer

question mark

What will the code output?

Select the correct answer

question mark

You need to assemble a long string from many small pieces. What's recommended?

Select the correct answer

Tutto è chiaro?

Come possiamo migliorarlo?

Grazie per i tuoi commenti!

Sezione 3. Capitolo 4
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