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Dealing with Dates and Times in Python
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Dealing with Dates and Times in Python

Dealing with Dates and Times in Python

1. Working with Dates
What Day is it Today?Creating a Date ObjectDate AttributesDate MethodsDate FormatsOne More FormattingDate DifferenceArithmetic Operations with timedelta Objects
2. Working with Times
What Time is it Now?Creating a datetime ObjectDatetime AttributesDatetime MethodsDatetime Formats12-Hour and 24-Hour FormatsDate and Time DifferenceReading Date and Time from String
3. Timezones and Daylight Savings Time (DST)
The Variery of TimezonesTimezone ExamplesApplying Timezone to Datetime ObjectWhat Time is it in ... ?Daylight Savings Time
4. Working with Dates and Times in pandas
Challenge: What Will We Work With?Challenge: Converting Columns into datetime TypeChallenge: Extreme Trips DurationsChallenge: InvestigationChallenge: Negative Trip DurationChallenge: Is this Common Issue?Challenge: Fixing the IssuesChallenge: Average Metrics Across Taxi TypesChallenge: Corrected Metrics Across Taxi TypesChallenge: Group by Period?

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Challenge: Is this Common Issue?

In the previous chapter, we found out that issues with negative durations happened because of misusage of 12-h and 24-h formats. We printed the first 10 rows and saw that in all of these rides dropoff_calculated has the same minute and second (accurate to 1 second), but hours differ by 12.

Let's continue our investigation!

Tâche

Swipe to start coding

  1. Filter the observations in df dataframe to only with negative duration. Save it in df_neg variable.
  2. Iterate over rows of df_ned. If minute in dropoff_datetime and dropoff_calculated is not the same, you need to print this row.
  3. Within the same for loop count number of rows having an hour in dropoff_datetime greater or equal than 12.

Solution

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Tout était clair ?

Comment pouvons-nous l'améliorer ?

Merci pour vos commentaires !

Section 4. Chapitre 6
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book
Challenge: Is this Common Issue?

In the previous chapter, we found out that issues with negative durations happened because of misusage of 12-h and 24-h formats. We printed the first 10 rows and saw that in all of these rides dropoff_calculated has the same minute and second (accurate to 1 second), but hours differ by 12.

Let's continue our investigation!

Tâche

Swipe to start coding

  1. Filter the observations in df dataframe to only with negative duration. Save it in df_neg variable.
  2. Iterate over rows of df_ned. If minute in dropoff_datetime and dropoff_calculated is not the same, you need to print this row.
  3. Within the same for loop count number of rows having an hour in dropoff_datetime greater or equal than 12.

Solution

Switch to desktopPassez à un bureau pour une pratique réelleContinuez d'où vous êtes en utilisant l'une des options ci-dessous
Tout était clair ?

Comment pouvons-nous l'améliorer ?

Merci pour vos commentaires !

Section 4. Chapitre 6
Switch to desktopPassez à un bureau pour une pratique réelleContinuez d'où vous êtes en utilisant l'une des options ci-dessous
Nous sommes désolés de vous informer que quelque chose s'est mal passé. Qu'est-il arrivé ?
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