Notice: This page requires JavaScript to function properly.
Please enable JavaScript in your browser settings or update your browser.
Apprendre Extracting and Transforming Data | Working with Structured Data Formats
Working with Strings and Data Formats

bookExtracting and Transforming Data

1234567891011
# Suppose you have CSV data loaded as a list of rows, where each row is a list of strings. rows = [ ["id", "name", "age", "city"], ["1", "Alice", "30", "New York"], ["2", "Bob", "25", "Los Angeles"], ["3", "Charlie", "35", "Chicago"] ] # To extract the "name" column (index 1) from all rows except the header: name_column = [row[1] for row in rows[1:]] print(name_column) # Output: ['Alice', 'Bob', 'Charlie']
copy

When working with structured data such as JSON, you often deal with a list of dictionaries, where each dictionary represents an object with key-value pairs. To extract values for a given key from all dictionaries in the list, use a list comprehension. For instance, if you have a list of dictionaries representing people and want to extract all ages, you can use [person["age"] for person in people]. This approach gives you a new list containing only the values associated with the specified key from each dictionary.

1. Which of the following is the best way to access a value for a specific key in a dictionary?

2. Which approaches can be used to extract a column from a list of lists?

question mark

Which of the following is the best way to access a value for a specific key in a dictionary?

Select the correct answer

question mark

Which approaches can be used to extract a column from a list of lists?

Select the correct answer

Tout était clair ?

Comment pouvons-nous l'améliorer ?

Merci pour vos commentaires !

Section 3. Chapitre 3

Demandez à l'IA

expand

Demandez à l'IA

ChatGPT

Posez n'importe quelle question ou essayez l'une des questions suggérées pour commencer notre discussion

Suggested prompts:

Can you show an example using a list of dictionaries instead of a list of lists?

How can I extract multiple columns at once from the CSV data?

What if some rows are missing the "name" value?

Awesome!

Completion rate improved to 6.67

bookExtracting and Transforming Data

Glissez pour afficher le menu

1234567891011
# Suppose you have CSV data loaded as a list of rows, where each row is a list of strings. rows = [ ["id", "name", "age", "city"], ["1", "Alice", "30", "New York"], ["2", "Bob", "25", "Los Angeles"], ["3", "Charlie", "35", "Chicago"] ] # To extract the "name" column (index 1) from all rows except the header: name_column = [row[1] for row in rows[1:]] print(name_column) # Output: ['Alice', 'Bob', 'Charlie']
copy

When working with structured data such as JSON, you often deal with a list of dictionaries, where each dictionary represents an object with key-value pairs. To extract values for a given key from all dictionaries in the list, use a list comprehension. For instance, if you have a list of dictionaries representing people and want to extract all ages, you can use [person["age"] for person in people]. This approach gives you a new list containing only the values associated with the specified key from each dictionary.

1. Which of the following is the best way to access a value for a specific key in a dictionary?

2. Which approaches can be used to extract a column from a list of lists?

question mark

Which of the following is the best way to access a value for a specific key in a dictionary?

Select the correct answer

question mark

Which approaches can be used to extract a column from a list of lists?

Select the correct answer

Tout était clair ?

Comment pouvons-nous l'améliorer ?

Merci pour vos commentaires !

Section 3. Chapitre 3
some-alt