Problem B. Minimum path
Let's traverse mat and update values in it: now mat[i][j] contains the path cost to cell [i, j]. How to reach that? You can get to the mat[i][j] from either mat[i-1][j] or mat[i][j-1] cell, that also contain the path cost to themselves. Thus, mat[i][j] can be updated as:
mat[i][j] += min(mat[i-1][j], mat[i][j-1]),
since you choose the minumum cost path between these two.
Note that some cells can be reached only from left or right, for example, mat[0][j] (only from mat[0][j-1]).
So, the goal is to traverse mat and update its values; after that, return path cost at mat[-1][-1].
123456789101112131415161718def minPath(mat): m, n = len(mat), len(mat[0]) for i in range(1, m): mat[i][0] += mat[i-1][0] for j in range(1, n): mat[0][j] += mat[0][j-1] for i in range(1, m): for j in range(1, n): mat[i][j] += min(mat[i-1][j], mat[i][j-1]) return mat[-1][-1] mat = [[10,1,23,4,5,1], [2,13,20,9,1,5], [14,3,3,6,12,7]] print(minPath(mat))
Merci pour vos commentaires !
single
Demandez à l'IA
Demandez à l'IA
Posez n'importe quelle question ou essayez l'une des questions suggérées pour commencer notre discussion
Résumer ce chapitre
Expliquer le code dans file
Expliquer pourquoi file ne résout pas la tâche
Awesome!
Completion rate improved to 8.33Problem B. Minimum path
Glissez pour afficher le menu
Let's traverse mat and update values in it: now mat[i][j] contains the path cost to cell [i, j]. How to reach that? You can get to the mat[i][j] from either mat[i-1][j] or mat[i][j-1] cell, that also contain the path cost to themselves. Thus, mat[i][j] can be updated as:
mat[i][j] += min(mat[i-1][j], mat[i][j-1]),
since you choose the minumum cost path between these two.
Note that some cells can be reached only from left or right, for example, mat[0][j] (only from mat[0][j-1]).
So, the goal is to traverse mat and update its values; after that, return path cost at mat[-1][-1].
123456789101112131415161718def minPath(mat): m, n = len(mat), len(mat[0]) for i in range(1, m): mat[i][0] += mat[i-1][0] for j in range(1, n): mat[0][j] += mat[0][j-1] for i in range(1, m): for j in range(1, n): mat[i][j] += min(mat[i-1][j], mat[i][j-1]) return mat[-1][-1] mat = [[10,1,23,4,5,1], [2,13,20,9,1,5], [14,3,3,6,12,7]] print(minPath(mat))
Passez à un bureau pour une pratique réelleContinuez d'où vous êtes en utilisant l'une des options ci-dessousMerci pour vos commentaires !
Awesome!
Completion rate improved to 8.33single
