Notice: This page requires JavaScript to function properly.
Please enable JavaScript in your browser settings or update your browser.
Oppiskele Generic Lambdas | Advanced Functional Patterns
Practice
Projects
Quizzes & Challenges
Quizzes
Challenges
/
C++ Functional Utilities

bookGeneric Lambdas

Generic lambdas in C++ allow you to write functions that operate on any type without specifying the type explicitly. This is made possible by using auto in the lambda parameter list. When you write a lambda like [&](const auto& value) { /*...*/ }, the compiler generates a unique version of the lambda for each type it is called with, similar to how templates work.

Using auto as a parameter type in lambdas offers several benefits:

  • Reduces the need for boilerplate code by eliminating explicit type declarations;
  • Makes your code more flexible and reusable, as the same lambda can handle different types;
  • Enables you to write concise, type-agnostic utilities that work seamlessly across various contexts;
  • Helps you avoid errors that can arise from manual type specification.

This approach is especially useful in generic programming and when working with algorithms that accept callable objects. You can pass a generic lambda to std::for_each, std::transform, or any function that expects a callable, and the lambda will adapt to the element type automatically.

main.cpp

main.cpp

copy
123456789101112131415161718192021222324252627282930313233
#include <iostream> #include <string> #include <vector> #include <algorithm> int main() { // Define a generic lambda that prints any type of value auto printValue = [](const auto& value) { std::cout << value << std::endl; }; // Use with an int printValue(42); // Use with a double printValue(3.1415); // Use with a string printValue(std::string("Hello, world!")); // Use with a vector (prints address since vector does not overload operator<<) std::vector<int> numbers = {1, 2, 3}; printValue(numbers.size()); // Use with an element from the vector printValue(numbers[1]); // Use with a char printValue('A'); return 0; }
question mark

What is the primary benefit of using auto parameters in generic lambdas?

Select the correct answer

Oliko kaikki selvää?

Miten voimme parantaa sitä?

Kiitos palautteestasi!

Osio 3. Luku 3

Kysy tekoälyä

expand

Kysy tekoälyä

ChatGPT

Kysy mitä tahansa tai kokeile jotakin ehdotetuista kysymyksistä aloittaaksesi keskustelumme

bookGeneric Lambdas

Pyyhkäise näyttääksesi valikon

Generic lambdas in C++ allow you to write functions that operate on any type without specifying the type explicitly. This is made possible by using auto in the lambda parameter list. When you write a lambda like [&](const auto& value) { /*...*/ }, the compiler generates a unique version of the lambda for each type it is called with, similar to how templates work.

Using auto as a parameter type in lambdas offers several benefits:

  • Reduces the need for boilerplate code by eliminating explicit type declarations;
  • Makes your code more flexible and reusable, as the same lambda can handle different types;
  • Enables you to write concise, type-agnostic utilities that work seamlessly across various contexts;
  • Helps you avoid errors that can arise from manual type specification.

This approach is especially useful in generic programming and when working with algorithms that accept callable objects. You can pass a generic lambda to std::for_each, std::transform, or any function that expects a callable, and the lambda will adapt to the element type automatically.

main.cpp

main.cpp

copy
123456789101112131415161718192021222324252627282930313233
#include <iostream> #include <string> #include <vector> #include <algorithm> int main() { // Define a generic lambda that prints any type of value auto printValue = [](const auto& value) { std::cout << value << std::endl; }; // Use with an int printValue(42); // Use with a double printValue(3.1415); // Use with a string printValue(std::string("Hello, world!")); // Use with a vector (prints address since vector does not overload operator<<) std::vector<int> numbers = {1, 2, 3}; printValue(numbers.size()); // Use with an element from the vector printValue(numbers[1]); // Use with a char printValue('A'); return 0; }
question mark

What is the primary benefit of using auto parameters in generic lambdas?

Select the correct answer

Oliko kaikki selvää?

Miten voimme parantaa sitä?

Kiitos palautteestasi!

Osio 3. Luku 3
some-alt