Mutable Default Arguments
Understanding how default arguments work in Python functions is crucial, especially when those arguments are mutable types such as lists or dictionaries. In Python, default argument values are evaluated only once at the time the function is defined, not each time the function is called. This means that if you use a mutable object like a list or dict as a default value, all calls to that function that do not provide that argument will share the same object.
1234567def add_item(item, items=[]): items.append(item) return items print(add_item("apple")) # Output: ['apple'] print(add_item("banana")) # Output: ['apple', 'banana'] print(add_item("orange")) # Output: ['apple', 'banana', 'orange']
This behavior can lead to confusing and unintended results. In the code sample above, each call to add_item without specifying the items argument modifies the same list. As a result, items accumulate across calls, which is rarely what you want. This happens because the default list is created once when the function is defined, and the same list is used every time the function is called without a new items argument.
To avoid this pitfall, you should use None as the default value for arguments that are intended to be mutable objects. Inside the function, you can then check if the argument is None and create a new list or dictionary as needed. This ensures that each call to the function gets its own fresh object, preventing unwanted sharing of state between calls.
Kiitos palautteestasi!
Kysy tekoälyä
Kysy tekoälyä
Kysy mitä tahansa tai kokeile jotakin ehdotetuista kysymyksistä aloittaaksesi keskustelumme
Awesome!
Completion rate improved to 5.26Mutable Default Arguments
Pyyhkäise näyttääksesi valikon
Understanding how default arguments work in Python functions is crucial, especially when those arguments are mutable types such as lists or dictionaries. In Python, default argument values are evaluated only once at the time the function is defined, not each time the function is called. This means that if you use a mutable object like a list or dict as a default value, all calls to that function that do not provide that argument will share the same object.
1234567def add_item(item, items=[]): items.append(item) return items print(add_item("apple")) # Output: ['apple'] print(add_item("banana")) # Output: ['apple', 'banana'] print(add_item("orange")) # Output: ['apple', 'banana', 'orange']
This behavior can lead to confusing and unintended results. In the code sample above, each call to add_item without specifying the items argument modifies the same list. As a result, items accumulate across calls, which is rarely what you want. This happens because the default list is created once when the function is defined, and the same list is used every time the function is called without a new items argument.
To avoid this pitfall, you should use None as the default value for arguments that are intended to be mutable objects. Inside the function, you can then check if the argument is None and create a new list or dictionary as needed. This ensures that each call to the function gets its own fresh object, preventing unwanted sharing of state between calls.
Kiitos palautteestasi!
