Aprende Pointers Brief Overview | Pointers and Structs

To go through the following chapters, I suggest briefly repeating the pointers in the C programming language.

Note

If you are not familiar with the basic skills of working with the C programming language, we recommend taking our basic C programming language course: C Basic

Dereferencing Operator

A pointer is a variable that contains the address of another object.

Dereference operator "*" returns the value stored at the address.

Declaring and initializing a pointer looks like this:

int* pName = NULL;

main.c


              12345678
            
#include <stdio.h>

int main() 
{
    int* pName = NULL;
    printf("%p\n", pName); // `%p` is a specifier for a pointer
    return 0;
}

Referencing Operator &

The "&" operator returns the address of an object:

main.c


              12345678
            
#include <stdio.h>

int main() 
{
    int variable;
    printf("%p\n", &variable);
    return 0;
}

A variable of pointer type is used to store the address, which is returned by the & operator.

int variable;
int* pVariable;
pVariable = &variable;

To "unpack" the contents at the specified address, you must use the * operator on a variable of type pointer.

main.c


              12345678910
            
 #include <stdio.h>

int main()
{
    int variable = 1024;
    int* pVariable = &variable;
    printf("Address: %p\n", pVariable); // `%p` specifier for a pointer
    printf("Returned value by address: %d\n", *(pVariable)); // using `*` to pointer
    return 0;
}

Tarea

Swipe to start coding

You have a product with a specific price, and you need to increase its value by a given percentage.
Your task is to implement a function that updates the product’s price using a pointer.

Inside the updatePrice function:

Use the dereference operator (*) to access the current value stored in memory — for example, *price refers to 100.0.
Calculate the percentage of the current price — *price * percentIncrease / 100.0, which for 10% of 100.0 equals 10.0.
Add this percentage to the original value to get the updated price — *price = *price + (percentage part).
The function doesn’t return anything — it directly modifies the value through the pointer.

Example

Initial Price	Increase (%)	Updated Price
100.0	10.0	110.0
250.0	5.0	262.5
80.0	25.0	100.0

Solución

¿Todo estuvo claro?

¡Gracias por tus comentarios!

Sección 2. Capítulo 1

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To go through the following chapters, I suggest briefly repeating the pointers in the C programming language.

Note

If you are not familiar with the basic skills of working with the C programming language, we recommend taking our basic C programming language course: C Basic

Dereferencing Operator

A pointer is a variable that contains the address of another object.

Dereference operator "*" returns the value stored at the address.

Declaring and initializing a pointer looks like this:

int* pName = NULL;

main.c


              12345678
            
#include <stdio.h>

int main() 
{
    int* pName = NULL;
    printf("%p\n", pName); // `%p` is a specifier for a pointer
    return 0;
}

Referencing Operator &

The "&" operator returns the address of an object:

main.c


              12345678
            
#include <stdio.h>

int main() 
{
    int variable;
    printf("%p\n", &variable);
    return 0;
}

A variable of pointer type is used to store the address, which is returned by the & operator.

int variable;
int* pVariable;
pVariable = &variable;

To "unpack" the contents at the specified address, you must use the * operator on a variable of type pointer.

main.c


              12345678910
            
 #include <stdio.h>

int main()
{
    int variable = 1024;
    int* pVariable = &variable;
    printf("Address: %p\n", pVariable); // `%p` specifier for a pointer
    printf("Returned value by address: %d\n", *(pVariable)); // using `*` to pointer
    return 0;
}

Tarea

Swipe to start coding

Inside the updatePrice function:

Use the dereference operator (*) to access the current value stored in memory — for example, *price refers to 100.0.
Calculate the percentage of the current price — *price * percentIncrease / 100.0, which for 10% of 100.0 equals 10.0.
Add this percentage to the original value to get the updated price — *price = *price + (percentage part).
The function doesn’t return anything — it directly modifies the value through the pointer.

Example

Initial Price	Increase (%)	Updated Price
100.0	10.0	110.0
250.0	5.0	262.5
80.0	25.0	100.0

Solución

Cambia al escritorio para practicar en el mundo realContinúe desde donde se encuentra utilizando una de las siguientes opciones

¿Todo estuvo claro?

¡Gracias por tus comentarios!

Sección 2. Capítulo 1

single