Notice: This page requires JavaScript to function properly.
Please enable JavaScript in your browser settings or update your browser.Break/Continue in a Nested Loop | Nested Loops
Python Loops Tutorial
course content

Contenido del Curso

Python Loops Tutorial

Python Loops Tutorial

1. The for Loop
The first for LoopRange() in a for Loop 1/2Range() in a for Loop 2/2List & for LoopIf/Else in a for LoopBreak/Continue in a for LoopPass, Else in a for LoopEnumerate() in a for LoopChallenge
2. The while Loop
The First while LoopInfinite LoopList & while LoopIf/Else in a while LoopBreak/Continue in a while LoopPass, Else in a while Loop
3. Nested Loops
First Nested Loop PatternNested for LoopNested while LoopWhile Loop inside a for LoopIf/Else in a Nested LoopBreak/Continue in a Nested LoopChallenge

bookBreak/Continue in a Nested Loop

If the break statement is employed within a nested loop, it will terminate the innermost loop.

Examine the code below:


              
12345678

            
# Not allowing the nested loop to work for j == 3 and i == 2
for i in range(4):
  if i == 2:
      break
  for j in range(4):
    if j == 3:
      break
    print(i, j)
copy

How does the code work?

Please note that when the continue statement is encountered inside the loop, it skips all the statements below it and immediately moves to the next iteration.

Examine the code below:


              
12345678910

            
numbers_1 = [1, 2, 3]
numbers_2 = [1, 2, 4]

# Printing the sum of number_1 and number_2 elements, ignoring the sum of the same elements
for i in numbers_1:
  for j in numbers_2:
    if i == j:
      continue
    else:
      print(i, '+', j, '= ', i + j)
copy

How does the code work?

Tarea
test

Swipe to show code editor

You need to filter out symbols and numbers from the given list.

  1. Configure the outer for loop to iterate through the number of rows in the matrix.
  2. Configure the inner for loop to iterate through the elements in each row of the matrix.
  3. Implement the following conditions: If an element is '#', then continue the loop; else if an element is '!', then break out of the loop; if an element is neither '#' nor '!', then print this element.

Switch to desktopCambia al escritorio para practicar en el mundo realContinúe desde donde se encuentra utilizando una de las siguientes opciones
¿Todo estuvo claro?

¿Cómo podemos mejorarlo?

¡Gracias por tus comentarios!

Sección 3. Capítulo 6
toggle bottom row

bookBreak/Continue in a Nested Loop

If the break statement is employed within a nested loop, it will terminate the innermost loop.

Examine the code below:


              
12345678

            
# Not allowing the nested loop to work for j == 3 and i == 2
for i in range(4):
  if i == 2:
      break
  for j in range(4):
    if j == 3:
      break
    print(i, j)
copy

How does the code work?

Please note that when the continue statement is encountered inside the loop, it skips all the statements below it and immediately moves to the next iteration.

Examine the code below:


              
12345678910

            
numbers_1 = [1, 2, 3]
numbers_2 = [1, 2, 4]

# Printing the sum of number_1 and number_2 elements, ignoring the sum of the same elements
for i in numbers_1:
  for j in numbers_2:
    if i == j:
      continue
    else:
      print(i, '+', j, '= ', i + j)
copy

How does the code work?

Tarea
test

Swipe to show code editor

You need to filter out symbols and numbers from the given list.

  1. Configure the outer for loop to iterate through the number of rows in the matrix.
  2. Configure the inner for loop to iterate through the elements in each row of the matrix.
  3. Implement the following conditions: If an element is '#', then continue the loop; else if an element is '!', then break out of the loop; if an element is neither '#' nor '!', then print this element.

Switch to desktopCambia al escritorio para practicar en el mundo realContinúe desde donde se encuentra utilizando una de las siguientes opciones
¿Todo estuvo claro?

¿Cómo podemos mejorarlo?

¡Gracias por tus comentarios!

Sección 3. Capítulo 6
toggle bottom row

bookBreak/Continue in a Nested Loop

If the break statement is employed within a nested loop, it will terminate the innermost loop.

Examine the code below:


              
12345678

            
# Not allowing the nested loop to work for j == 3 and i == 2
for i in range(4):
  if i == 2:
      break
  for j in range(4):
    if j == 3:
      break
    print(i, j)
copy

How does the code work?

Please note that when the continue statement is encountered inside the loop, it skips all the statements below it and immediately moves to the next iteration.

Examine the code below:


              
12345678910

            
numbers_1 = [1, 2, 3]
numbers_2 = [1, 2, 4]

# Printing the sum of number_1 and number_2 elements, ignoring the sum of the same elements
for i in numbers_1:
  for j in numbers_2:
    if i == j:
      continue
    else:
      print(i, '+', j, '= ', i + j)
copy

How does the code work?

Tarea
test

Swipe to show code editor

You need to filter out symbols and numbers from the given list.

  1. Configure the outer for loop to iterate through the number of rows in the matrix.
  2. Configure the inner for loop to iterate through the elements in each row of the matrix.
  3. Implement the following conditions: If an element is '#', then continue the loop; else if an element is '!', then break out of the loop; if an element is neither '#' nor '!', then print this element.

Switch to desktopCambia al escritorio para practicar en el mundo realContinúe desde donde se encuentra utilizando una de las siguientes opciones
¿Todo estuvo claro?

¿Cómo podemos mejorarlo?

¡Gracias por tus comentarios!

If the break statement is employed within a nested loop, it will terminate the innermost loop.

Examine the code below:


              
12345678

            
# Not allowing the nested loop to work for j == 3 and i == 2
for i in range(4):
  if i == 2:
      break
  for j in range(4):
    if j == 3:
      break
    print(i, j)
copy

How does the code work?

Please note that when the continue statement is encountered inside the loop, it skips all the statements below it and immediately moves to the next iteration.

Examine the code below:


              
12345678910

            
numbers_1 = [1, 2, 3]
numbers_2 = [1, 2, 4]

# Printing the sum of number_1 and number_2 elements, ignoring the sum of the same elements
for i in numbers_1:
  for j in numbers_2:
    if i == j:
      continue
    else:
      print(i, '+', j, '= ', i + j)
copy

How does the code work?

Tarea
test

Swipe to show code editor

You need to filter out symbols and numbers from the given list.

  1. Configure the outer for loop to iterate through the number of rows in the matrix.
  2. Configure the inner for loop to iterate through the elements in each row of the matrix.
  3. Implement the following conditions: If an element is '#', then continue the loop; else if an element is '!', then break out of the loop; if an element is neither '#' nor '!', then print this element.

Switch to desktopCambia al escritorio para practicar en el mundo realContinúe desde donde se encuentra utilizando una de las siguientes opciones
Sección 3. Capítulo 6
Switch to desktopCambia al escritorio para practicar en el mundo realContinúe desde donde se encuentra utilizando una de las siguientes opciones
We're sorry to hear that something went wrong. What happened?
some-alt