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Lernen Pointers to Structs | Pointers and Structs
C Structs

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Pointers to Structs

The C programming language allows you to create pointers not only to regular data types but also to structures (since a structure is a custom data type).

Declaration and initialization of a pointer looks like this:

If <name_of_pointer> is a pointer to a structure,
then *(<name_of_pointer>) is the structure itself.

To access the fields of a structure through a pointer, you must use the -> operator.

Note

"->" is an analogue of the structure access operator .

c

main

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#include <stdio.h> // structure declaration struct Point { int x; int y; }; int main() { // create a structure variable of Point type struct Point p1; p1.x = 10; p1.y = 20; // create a pointer to a structure of type Point and assign it the address of variable p1 struct Point* ptr = &p1; // Access structure members via pointer by `->` operator printf("Coordinates: (%d, %d)\n", ptr->x, ptr->y); return 0; }
Aufgabe

Swipe to start coding

  1. Declare structure Human which contains two fields name and age;
  2. Initialize the structure worker and fill the fields;
  3. Declare and initialize a pointer ptr to a worker;
  4. Display information about the worker.

Lösung

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book
Pointers to Structs

The C programming language allows you to create pointers not only to regular data types but also to structures (since a structure is a custom data type).

Declaration and initialization of a pointer looks like this:

If <name_of_pointer> is a pointer to a structure,
then *(<name_of_pointer>) is the structure itself.

To access the fields of a structure through a pointer, you must use the -> operator.

Note

"->" is an analogue of the structure access operator .

c

main

copy
12345678910111213141516171819202122
#include <stdio.h> // structure declaration struct Point { int x; int y; }; int main() { // create a structure variable of Point type struct Point p1; p1.x = 10; p1.y = 20; // create a pointer to a structure of type Point and assign it the address of variable p1 struct Point* ptr = &p1; // Access structure members via pointer by `->` operator printf("Coordinates: (%d, %d)\n", ptr->x, ptr->y); return 0; }
Aufgabe

Swipe to start coding

  1. Declare structure Human which contains two fields name and age;
  2. Initialize the structure worker and fill the fields;
  3. Declare and initialize a pointer ptr to a worker;
  4. Display information about the worker.

Lösung

Switch to desktopWechseln Sie zum Desktop, um in der realen Welt zu übenFahren Sie dort fort, wo Sie sind, indem Sie eine der folgenden Optionen verwenden
War alles klar?

Wie können wir es verbessern?

Danke für Ihr Feedback!

close

Awesome!

Completion rate improved to 4.17

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