Basic Concept and Structure
A linked list in C is a simple dynamic data structure consisting of elements called nodes. Each node contains data (such as a variable or object) as well as a pointer to the next node in the list.
Here's what a typical node in a singly linked list looks like in C:
If instead of a pointer to the next node you try to simply create an instance of a new node, you will get an error.
The compiler will not be able to allocate memory for such a structure, since it contains itself. It's like trying to look at yourself from the outside with your own eyes
Using a pointer solves this problem because the compiler knows how much memory to allocate for a pointer variable.
The last node pointer will always be NULL.
Swipe to start coding
Create a function createNode that dynamically allocates memory for a new linked list node. The function should initialize the data field with the given value and set the next pointer to NULL.
Then, in main, create several nodes, link them together, and print the linked list.
- Inside
createNode, allocate memory for a new node usingmallocand cast it to(struct Node*). - Check if memory allocation failed. If
newNodeisNULL, print an error message and returnNULL. - Initialize the
datafield of the new node with thevalueparameter. - Set the
nextpointer of the new node toNULL. - Return the pointer to the newly created node.
Lösung
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Can you explain how to define a node structure for a linked list in C?
Why does using a pointer in the node structure solve the memory allocation problem?
Can you give an example of how to create and link nodes in a linked list?
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Basic Concept and Structure
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A linked list in C is a simple dynamic data structure consisting of elements called nodes. Each node contains data (such as a variable or object) as well as a pointer to the next node in the list.
Here's what a typical node in a singly linked list looks like in C:
If instead of a pointer to the next node you try to simply create an instance of a new node, you will get an error.
The compiler will not be able to allocate memory for such a structure, since it contains itself. It's like trying to look at yourself from the outside with your own eyes
Using a pointer solves this problem because the compiler knows how much memory to allocate for a pointer variable.
The last node pointer will always be NULL.
Swipe to start coding
Create a function createNode that dynamically allocates memory for a new linked list node. The function should initialize the data field with the given value and set the next pointer to NULL.
Then, in main, create several nodes, link them together, and print the linked list.
- Inside
createNode, allocate memory for a new node usingmallocand cast it to(struct Node*). - Check if memory allocation failed. If
newNodeisNULL, print an error message and returnNULL. - Initialize the
datafield of the new node with thevalueparameter. - Set the
nextpointer of the new node toNULL. - Return the pointer to the newly created node.
Lösung
Danke für Ihr Feedback!
single