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Lernen Challenge: Abstraction | Section
Java Object-Oriented Programming (OOP) Fundamentals

bookChallenge: Abstraction

Task

An abstract class called Shape has been created for you. It contains two abstract methods: calculateArea() and calculatePerimeter(). Your task is to implement two classes: Rectangle and Circle. You need to inherit these classes from the abstract class Shape and override its methods. Here's a brief guide:

  • For the Circle class, you will need fields such as radius, and for the Rectangle class, you will need fields like width and height. These fields and their constructors are already provided for you. Use these fields when overriding the methods.

  • If you don't have strong geometry knowledge, here's a quick reference with formulas you need to use:

    • Circle Area: Pi * radius * radius;
    • Circle Perimeter: 2 * PI * radius;
    • Rectangle Area: width * height;
    • Rectangle Perimeter: 2 * (width + height).

To use the value of π (PI), make use of the Math library. You can use Math.PI to access the value of π.

War alles klar?

Wie können wir es verbessern?

Danke für Ihr Feedback!

Abschnitt 1. Kapitel 23

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bookChallenge: Abstraction

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Task

An abstract class called Shape has been created for you. It contains two abstract methods: calculateArea() and calculatePerimeter(). Your task is to implement two classes: Rectangle and Circle. You need to inherit these classes from the abstract class Shape and override its methods. Here's a brief guide:

  • For the Circle class, you will need fields such as radius, and for the Rectangle class, you will need fields like width and height. These fields and their constructors are already provided for you. Use these fields when overriding the methods.

  • If you don't have strong geometry knowledge, here's a quick reference with formulas you need to use:

    • Circle Area: Pi * radius * radius;
    • Circle Perimeter: 2 * PI * radius;
    • Rectangle Area: width * height;
    • Rectangle Perimeter: 2 * (width + height).

To use the value of π (PI), make use of the Math library. You can use Math.PI to access the value of π.

War alles klar?

Wie können wir es verbessern?

Danke für Ihr Feedback!

Abschnitt 1. Kapitel 23
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