Lære Returning Lambdas | Advanced Functional Patterns

When you return a lambda from a function, C++ can often deduce the return type automatically using auto. This is convenient and keeps your code concise. However, there are cases where you might want to specify an explicit return type, such as std::function, for greater flexibility.

Using std::function as the return type allows you to return any callable object matching the signature, not just a specific lambda. This can be helpful if you want to change the implementation later, or if you need to store different types of callables in a container or pass them around in your code. However, using std::function may introduce some overhead compared to using auto-deduced lambdas directly, so you should choose the approach that best fits your needs.

main.cpp


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#include <iostream>
#include <functional>

// Function returning a lambda that multiplies by a captured factor
auto make_multiplier(int factor) {
    // The lambda captures 'factor' by value
    return [factor](int x) { return x * factor; };
}

int main() {
    // Create a multiplier that multiplies by 5
    auto times_five = make_multiplier(5);

    std::cout << "3 * 5 = " << times_five(3) << std::endl; // Output: 15

    // Using std::function as the return type
    std::function<int(int)> times_ten = make_multiplier(10);
    std::cout << "4 * 10 = " << times_ten(4) << std::endl; // Output: 40

    return 0;
}

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main.cpp


              12345678910111213141516171819202122
            
#include <iostream>
#include <functional>

// Function returning a lambda that multiplies by a captured factor
auto make_multiplier(int factor) {
    // The lambda captures 'factor' by value
    return [factor](int x) { return x * factor; };
}

int main() {
    // Create a multiplier that multiplies by 5
    auto times_five = make_multiplier(5);

    std::cout << "3 * 5 = " << times_five(3) << std::endl; // Output: 15

    // Using std::function as the return type
    std::function<int(int)> times_ten = make_multiplier(10);
    std::cout << "4 * 10 = " << times_ten(4) << std::endl; // Output: 40

    return 0;
}

Var alt klart?

Tak for dine kommentarer!

Sektion 3. Kapitel 2