Course Content
Explore the Linear Regression Using Python
Explore the Linear Regression Using Python
Prediction
Once we've trained our module, it's time to think about test data evaluation and future predictions. We can make predictions using the method predict()
.
Let's look at an example. Prediction for flavanoids when the number of total phenols is 1:
new_total_phenols = np.array([1]).reshape(-1,1) print(model.predict(new_total_phenols))
Method
.reshape()
gives a new shape to an array without changing its data. Input must be a 2-dimension (DataFrame or 2-dimension array will work here).
This value is the same as if we had substituted the line b + kx, where b is the estimated intersection with the model, and k is the slope. Please note that we multiply by 1 since the number of total phenols is 1 (x = 1).
prediction = model.intercept_ + model.coef_*1
We can also put our testing data to get predictions for all amounts of flavanoids:
y_test_predicted = model.predict(X_test)
Task
Predict with the previous split-train data the amount of flavanoids if the total phenols is 2.
- [Line #6] Import the
numpy
library. - [Line #26] Initialize the linear regression model.
- [Line #30] Assign
np.array()
and number of total phenols as the parameter (2) to the variablenew_total_phenols
(don’t forget to use the function.reshape(-1,1)
). - [Line #31] Predict amount of flavanoids
- [Line #32] Print the predicted amount of flavanoids.
Thanks for your feedback!
Prediction
Once we've trained our module, it's time to think about test data evaluation and future predictions. We can make predictions using the method predict()
.
Let's look at an example. Prediction for flavanoids when the number of total phenols is 1:
new_total_phenols = np.array([1]).reshape(-1,1) print(model.predict(new_total_phenols))
Method
.reshape()
gives a new shape to an array without changing its data. Input must be a 2-dimension (DataFrame or 2-dimension array will work here).
This value is the same as if we had substituted the line b + kx, where b is the estimated intersection with the model, and k is the slope. Please note that we multiply by 1 since the number of total phenols is 1 (x = 1).
prediction = model.intercept_ + model.coef_*1
We can also put our testing data to get predictions for all amounts of flavanoids:
y_test_predicted = model.predict(X_test)
Task
Predict with the previous split-train data the amount of flavanoids if the total phenols is 2.
- [Line #6] Import the
numpy
library. - [Line #26] Initialize the linear regression model.
- [Line #30] Assign
np.array()
and number of total phenols as the parameter (2) to the variablenew_total_phenols
(don’t forget to use the function.reshape(-1,1)
). - [Line #31] Predict amount of flavanoids
- [Line #32] Print the predicted amount of flavanoids.
Thanks for your feedback!
Prediction
Once we've trained our module, it's time to think about test data evaluation and future predictions. We can make predictions using the method predict()
.
Let's look at an example. Prediction for flavanoids when the number of total phenols is 1:
new_total_phenols = np.array([1]).reshape(-1,1) print(model.predict(new_total_phenols))
Method
.reshape()
gives a new shape to an array without changing its data. Input must be a 2-dimension (DataFrame or 2-dimension array will work here).
This value is the same as if we had substituted the line b + kx, where b is the estimated intersection with the model, and k is the slope. Please note that we multiply by 1 since the number of total phenols is 1 (x = 1).
prediction = model.intercept_ + model.coef_*1
We can also put our testing data to get predictions for all amounts of flavanoids:
y_test_predicted = model.predict(X_test)
Task
Predict with the previous split-train data the amount of flavanoids if the total phenols is 2.
- [Line #6] Import the
numpy
library. - [Line #26] Initialize the linear regression model.
- [Line #30] Assign
np.array()
and number of total phenols as the parameter (2) to the variablenew_total_phenols
(don’t forget to use the function.reshape(-1,1)
). - [Line #31] Predict amount of flavanoids
- [Line #32] Print the predicted amount of flavanoids.
Thanks for your feedback!
Once we've trained our module, it's time to think about test data evaluation and future predictions. We can make predictions using the method predict()
.
Let's look at an example. Prediction for flavanoids when the number of total phenols is 1:
new_total_phenols = np.array([1]).reshape(-1,1) print(model.predict(new_total_phenols))
Method
.reshape()
gives a new shape to an array without changing its data. Input must be a 2-dimension (DataFrame or 2-dimension array will work here).
This value is the same as if we had substituted the line b + kx, where b is the estimated intersection with the model, and k is the slope. Please note that we multiply by 1 since the number of total phenols is 1 (x = 1).
prediction = model.intercept_ + model.coef_*1
We can also put our testing data to get predictions for all amounts of flavanoids:
y_test_predicted = model.predict(X_test)
Task
Predict with the previous split-train data the amount of flavanoids if the total phenols is 2.
- [Line #6] Import the
numpy
library. - [Line #26] Initialize the linear regression model.
- [Line #30] Assign
np.array()
and number of total phenols as the parameter (2) to the variablenew_total_phenols
(don’t forget to use the function.reshape(-1,1)
). - [Line #31] Predict amount of flavanoids
- [Line #32] Print the predicted amount of flavanoids.