Course Content

Dealing with Dates and Times in Python

1. Working with Dates

What Day is it Today?Creating a Date Object Date Attributes Date Methods Date Formats One More Formatting Date Difference Arithmetic Operations with timedelta Objects

2. Working with Times

What Time is it Now?Creating a datetime Object Datetime Attributes Datetime Methods Datetime Formats 12-Hour and 24-Hour Formats Date and Time Difference Reading Date and Time from String

3. Timezones and Daylight Savings Time (DST)

The Variery of Timezones Timezone Examples Applying Timezone to Datetime Object What Time is it in ... ?Daylight Savings Time

4. Working with Dates and Times in pandas

Challenge: What Will We Work With?Challenge: Converting Columns into datetime Type Challenge: Extreme Trips Durations Challenge: Investigation Challenge: Negative Trip Duration Challenge: Is this Common Issue?Challenge: Fixing the Issues Challenge: Average Metrics Across Taxi Types Challenge: Corrected Metrics Across Taxi Types Challenge: Group by Period?

Date Methods

There are also several methods available for date objects. Let's consider some of them:

date.weekday() - returns the day of week as an integer (0 is Monday, 6 is Sunday);
date.isoweekday() - returns the day of week as an integer (but this time 1 for Monday, and 7 for Sunday);
date.replace(year = ..., month = ..., day = ...) - replaces the specified arguments for given date object.

For example, using the date from the previous example (1st of November 2021) we can say what day of the week that was. Then, using .replace() method we can change the year to 2022 and see what day of the week it will be. For a change, let's use both .weekday() and .isoweekday() methods.


              123456789101112
            
# Load class from library
from datetime import date

# Create date object
course_created = date(2021, 11, 1)

# Print day of week for given date
print(course_created.weekday())
# Replace year to 2022
next_year = course_created.replace(year = 2022)
# Find out what day of week it will be
print(next_year.isoweekday())

We got two numbers: 0 and 2. What do they mean? We got 0 from .weekday() method which returns Monday as 0 and so on. So, the 1st of November 2021 was Monday. Then, we added to this date 1 year and .isoweekday() returned 2. In this case that will be Tuesday, as .isoweekday() method returns 1 for Monday and so on.

Now let's find out Halloween's days of the week.

Task

Assign date October 31, 2021, to variable halloween.
Find out the day of the week for this date.
Using .replace method create new variable halloween_next and assign the date halloween but with the next year (2022).
Find out the day of the week for halloween_next. Feel free to use either .weekday() or .isoweekday() methods.

Task

Assign date October 31, 2021, to variable halloween.
Find out the day of the week for this date.
Using .replace method create new variable halloween_next and assign the date halloween but with the next year (2022).
Find out the day of the week for halloween_next. Feel free to use either .weekday() or .isoweekday() methods.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Section 1. Chapter 4

Date Methods

There are also several methods available for date objects. Let's consider some of them:

date.weekday() - returns the day of week as an integer (0 is Monday, 6 is Sunday);
date.isoweekday() - returns the day of week as an integer (but this time 1 for Monday, and 7 for Sunday);
date.replace(year = ..., month = ..., day = ...) - replaces the specified arguments for given date object.


              123456789101112
            
# Load class from library
from datetime import date

# Create date object
course_created = date(2021, 11, 1)

# Print day of week for given date
print(course_created.weekday())
# Replace year to 2022
next_year = course_created.replace(year = 2022)
# Find out what day of week it will be
print(next_year.isoweekday())

Now let's find out Halloween's days of the week.

Task

Assign date October 31, 2021, to variable halloween.
Find out the day of the week for this date.
Using .replace method create new variable halloween_next and assign the date halloween but with the next year (2022).
Find out the day of the week for halloween_next. Feel free to use either .weekday() or .isoweekday() methods.

Task

Assign date October 31, 2021, to variable halloween.
Find out the day of the week for this date.
Using .replace method create new variable halloween_next and assign the date halloween but with the next year (2022).
Find out the day of the week for halloween_next. Feel free to use either .weekday() or .isoweekday() methods.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Section 1. Chapter 4

Date Methods

There are also several methods available for date objects. Let's consider some of them:

date.weekday() - returns the day of week as an integer (0 is Monday, 6 is Sunday);
date.isoweekday() - returns the day of week as an integer (but this time 1 for Monday, and 7 for Sunday);
date.replace(year = ..., month = ..., day = ...) - replaces the specified arguments for given date object.


              123456789101112
            
# Load class from library
from datetime import date

# Create date object
course_created = date(2021, 11, 1)

# Print day of week for given date
print(course_created.weekday())
# Replace year to 2022
next_year = course_created.replace(year = 2022)
# Find out what day of week it will be
print(next_year.isoweekday())

Now let's find out Halloween's days of the week.

Task

Assign date October 31, 2021, to variable halloween.
Find out the day of the week for this date.
Using .replace method create new variable halloween_next and assign the date halloween but with the next year (2022).
Find out the day of the week for halloween_next. Feel free to use either .weekday() or .isoweekday() methods.

Task

Assign date October 31, 2021, to variable halloween.
Find out the day of the week for this date.
Using .replace method create new variable halloween_next and assign the date halloween but with the next year (2022).
Find out the day of the week for halloween_next. Feel free to use either .weekday() or .isoweekday() methods.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

There are also several methods available for date objects. Let's consider some of them:

date.weekday() - returns the day of week as an integer (0 is Monday, 6 is Sunday);
date.isoweekday() - returns the day of week as an integer (but this time 1 for Monday, and 7 for Sunday);
date.replace(year = ..., month = ..., day = ...) - replaces the specified arguments for given date object.


              123456789101112
            
# Load class from library
from datetime import date

# Create date object
course_created = date(2021, 11, 1)

# Print day of week for given date
print(course_created.weekday())
# Replace year to 2022
next_year = course_created.replace(year = 2022)
# Find out what day of week it will be
print(next_year.isoweekday())

Now let's find out Halloween's days of the week.

Task

Assign date October 31, 2021, to variable halloween.
Find out the day of the week for this date.
Using .replace method create new variable halloween_next and assign the date halloween but with the next year (2022).
Find out the day of the week for halloween_next. Feel free to use either .weekday() or .isoweekday() methods.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Section 1. Chapter 4

Switch to desktop for real-world practiceContinue from where you are using one of the options below