Course Content
Dealing with Dates and Times in Python
Dealing with Dates and Times in Python
Arithmetic Operations with timedelta Objects
We can perform different arithmetic operations for multiple timedelta
objects. For example, we can add, subtract, divide, find the whole part of division... What's the sense?
For example, we can calculate the whole number of weeks between two dates. Let's use the same example as before: we can calculate the whole number of weeks since the COVID-19 became a pandemic (declared by WHO). There are two ways to solve this task:
- Extract the number of days (by using
.days
) and then find the whole part of division by 7. - Find the whole part of the division of two
timedelta
objects.
# Load classes from library from datetime import date from datetime import timedelta # Create two date objects pandemic = date(2020, 3, 11) today = date.today() # Calculate difference between dates diff = today - pandemic # Count whole number of weeks: method 1 print(diff.days//7, "weeks passed since COVID-19 became pandemic") # Count whole number of weeks: method 2 print(diff//timedelta(weeks = 1), "weeks passed since COVID-19 became pandemic")
See: in the first method, we extracted the number of days and calculated the whole part of the division by 7. In the second method, we divided by timedelta
object with 1 week as an argument.
Task
For the same two date
objects as before (date1
and date2
with dates "14 January 2016" and "07 April 2019" respectively) calculate the whole number of weeks between these dates (the initial difference is saved in date_diff
). Use both methods described in the example.
Thanks for your feedback!
Arithmetic Operations with timedelta Objects
We can perform different arithmetic operations for multiple timedelta
objects. For example, we can add, subtract, divide, find the whole part of division... What's the sense?
For example, we can calculate the whole number of weeks between two dates. Let's use the same example as before: we can calculate the whole number of weeks since the COVID-19 became a pandemic (declared by WHO). There are two ways to solve this task:
- Extract the number of days (by using
.days
) and then find the whole part of division by 7. - Find the whole part of the division of two
timedelta
objects.
# Load classes from library from datetime import date from datetime import timedelta # Create two date objects pandemic = date(2020, 3, 11) today = date.today() # Calculate difference between dates diff = today - pandemic # Count whole number of weeks: method 1 print(diff.days//7, "weeks passed since COVID-19 became pandemic") # Count whole number of weeks: method 2 print(diff//timedelta(weeks = 1), "weeks passed since COVID-19 became pandemic")
See: in the first method, we extracted the number of days and calculated the whole part of the division by 7. In the second method, we divided by timedelta
object with 1 week as an argument.
Task
For the same two date
objects as before (date1
and date2
with dates "14 January 2016" and "07 April 2019" respectively) calculate the whole number of weeks between these dates (the initial difference is saved in date_diff
). Use both methods described in the example.
Thanks for your feedback!
Arithmetic Operations with timedelta Objects
We can perform different arithmetic operations for multiple timedelta
objects. For example, we can add, subtract, divide, find the whole part of division... What's the sense?
For example, we can calculate the whole number of weeks between two dates. Let's use the same example as before: we can calculate the whole number of weeks since the COVID-19 became a pandemic (declared by WHO). There are two ways to solve this task:
- Extract the number of days (by using
.days
) and then find the whole part of division by 7. - Find the whole part of the division of two
timedelta
objects.
# Load classes from library from datetime import date from datetime import timedelta # Create two date objects pandemic = date(2020, 3, 11) today = date.today() # Calculate difference between dates diff = today - pandemic # Count whole number of weeks: method 1 print(diff.days//7, "weeks passed since COVID-19 became pandemic") # Count whole number of weeks: method 2 print(diff//timedelta(weeks = 1), "weeks passed since COVID-19 became pandemic")
See: in the first method, we extracted the number of days and calculated the whole part of the division by 7. In the second method, we divided by timedelta
object with 1 week as an argument.
Task
For the same two date
objects as before (date1
and date2
with dates "14 January 2016" and "07 April 2019" respectively) calculate the whole number of weeks between these dates (the initial difference is saved in date_diff
). Use both methods described in the example.
Thanks for your feedback!
We can perform different arithmetic operations for multiple timedelta
objects. For example, we can add, subtract, divide, find the whole part of division... What's the sense?
For example, we can calculate the whole number of weeks between two dates. Let's use the same example as before: we can calculate the whole number of weeks since the COVID-19 became a pandemic (declared by WHO). There are two ways to solve this task:
- Extract the number of days (by using
.days
) and then find the whole part of division by 7. - Find the whole part of the division of two
timedelta
objects.
# Load classes from library from datetime import date from datetime import timedelta # Create two date objects pandemic = date(2020, 3, 11) today = date.today() # Calculate difference between dates diff = today - pandemic # Count whole number of weeks: method 1 print(diff.days//7, "weeks passed since COVID-19 became pandemic") # Count whole number of weeks: method 2 print(diff//timedelta(weeks = 1), "weeks passed since COVID-19 became pandemic")
See: in the first method, we extracted the number of days and calculated the whole part of the division by 7. In the second method, we divided by timedelta
object with 1 week as an argument.
Task
For the same two date
objects as before (date1
and date2
with dates "14 January 2016" and "07 April 2019" respectively) calculate the whole number of weeks between these dates (the initial difference is saved in date_diff
). Use both methods described in the example.