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C Structs
course content

Course Content

C Structs

C Structs

1. Introduction to Structs
What are StructsStructs ApplicationDefining and Declaring StructsCreating Your First StructAccessing Struct Fields
2. Pointers and Structs
Pointers Brief OverviewPointers to StructsPointers Inside StructsDynamically Allocating StructsPassing Structs to the Functions
3. Structs and Memory
Understanding Memory Layout of StructsAlignment and Padding in StructsUnionsArrays with Structs
4. Advanced Structs Usage
Nested StructsStruct with Arrays and Other StructsAnonymous Struct and UnionComplex Data Structure
5. Implementing Data Structures
Introduction to Linked ListBasic Concept and StructureBuilding a Linked ListTravesting and Displaying Linked ListCompletionOverview

Pointers Brief Overview

To go through the following chapters, I suggest briefly repeating the pointers in the C programming language.

Note

If you are not familiar with the basic skills of working with the C programming language, we recommend taking our basic C programming language course: C Basic

Dereferencing Operator

A pointer is a variable that contains the address of another object.

Dereference operator "*" returns the value stored at the address.

Declaring and initializing a pointer looks like this:

c

main

copy

              
12345678

            
#include <stdio.h>

int main() 
{
    int* pName = NULL;
    printf("%p\n", pName); // `%p` is a specifier for a pointer
    return 0;
}

Referencing Operator &

The "&" operator returns the address of an object:

c

main

copy

              
12345678

            
#include <stdio.h>

int main() 
{
    int variable;
    printf("%p\n", &variable);
    return 0;
}

A variable of pointer type is used to store the address, which is returned by the & operator.

To "unpack" the contents at the specified address, you must use the * operator on a variable of type pointer.

c

main

copy

              
12345678910

            
 #include <stdio.h>

int main()
{
    int variable = 1024;
    int* pVariable = &variable;
    printf("Address: %p\n", pVariable); // `%p` specifier for a pointer
    printf("Returned value by address: %d\n", *(pVariable)); // using `*` to pointer
    return 0;
}

Task

  1. Declare and initialize any variable with any value;
  2. Declare a pointer to the same data type as your variable;
  3. Assign the address of a variable to a pointer;
  4. Display an address of your variable;
  5. Display the value of the variable by the pointer.

Task

  1. Declare and initialize any variable with any value;
  2. Declare a pointer to the same data type as your variable;
  3. Assign the address of a variable to a pointer;
  4. Display an address of your variable;
  5. Display the value of the variable by the pointer.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Section 2. Chapter 1
toggle bottom row

Pointers Brief Overview

To go through the following chapters, I suggest briefly repeating the pointers in the C programming language.

Note

If you are not familiar with the basic skills of working with the C programming language, we recommend taking our basic C programming language course: C Basic

Dereferencing Operator

A pointer is a variable that contains the address of another object.

Dereference operator "*" returns the value stored at the address.

Declaring and initializing a pointer looks like this:

c

main

copy

              
12345678

            
#include <stdio.h>

int main() 
{
    int* pName = NULL;
    printf("%p\n", pName); // `%p` is a specifier for a pointer
    return 0;
}

Referencing Operator &

The "&" operator returns the address of an object:

c

main

copy

              
12345678

            
#include <stdio.h>

int main() 
{
    int variable;
    printf("%p\n", &variable);
    return 0;
}

A variable of pointer type is used to store the address, which is returned by the & operator.

To "unpack" the contents at the specified address, you must use the * operator on a variable of type pointer.

c

main

copy

              
12345678910

            
 #include <stdio.h>

int main()
{
    int variable = 1024;
    int* pVariable = &variable;
    printf("Address: %p\n", pVariable); // `%p` specifier for a pointer
    printf("Returned value by address: %d\n", *(pVariable)); // using `*` to pointer
    return 0;
}

Task

  1. Declare and initialize any variable with any value;
  2. Declare a pointer to the same data type as your variable;
  3. Assign the address of a variable to a pointer;
  4. Display an address of your variable;
  5. Display the value of the variable by the pointer.

Task

  1. Declare and initialize any variable with any value;
  2. Declare a pointer to the same data type as your variable;
  3. Assign the address of a variable to a pointer;
  4. Display an address of your variable;
  5. Display the value of the variable by the pointer.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Section 2. Chapter 1
toggle bottom row

Pointers Brief Overview

To go through the following chapters, I suggest briefly repeating the pointers in the C programming language.

Note

If you are not familiar with the basic skills of working with the C programming language, we recommend taking our basic C programming language course: C Basic

Dereferencing Operator

A pointer is a variable that contains the address of another object.

Dereference operator "*" returns the value stored at the address.

Declaring and initializing a pointer looks like this:

c

main

copy

              
12345678

            
#include <stdio.h>

int main() 
{
    int* pName = NULL;
    printf("%p\n", pName); // `%p` is a specifier for a pointer
    return 0;
}

Referencing Operator &

The "&" operator returns the address of an object:

c

main

copy

              
12345678

            
#include <stdio.h>

int main() 
{
    int variable;
    printf("%p\n", &variable);
    return 0;
}

A variable of pointer type is used to store the address, which is returned by the & operator.

To "unpack" the contents at the specified address, you must use the * operator on a variable of type pointer.

c

main

copy

              
12345678910

            
 #include <stdio.h>

int main()
{
    int variable = 1024;
    int* pVariable = &variable;
    printf("Address: %p\n", pVariable); // `%p` specifier for a pointer
    printf("Returned value by address: %d\n", *(pVariable)); // using `*` to pointer
    return 0;
}

Task

  1. Declare and initialize any variable with any value;
  2. Declare a pointer to the same data type as your variable;
  3. Assign the address of a variable to a pointer;
  4. Display an address of your variable;
  5. Display the value of the variable by the pointer.

Task

  1. Declare and initialize any variable with any value;
  2. Declare a pointer to the same data type as your variable;
  3. Assign the address of a variable to a pointer;
  4. Display an address of your variable;
  5. Display the value of the variable by the pointer.

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

To go through the following chapters, I suggest briefly repeating the pointers in the C programming language.

Note

If you are not familiar with the basic skills of working with the C programming language, we recommend taking our basic C programming language course: C Basic

Dereferencing Operator

A pointer is a variable that contains the address of another object.

Dereference operator "*" returns the value stored at the address.

Declaring and initializing a pointer looks like this:

c

main

copy

              
12345678

            
#include <stdio.h>

int main() 
{
    int* pName = NULL;
    printf("%p\n", pName); // `%p` is a specifier for a pointer
    return 0;
}

Referencing Operator &

The "&" operator returns the address of an object:

c

main

copy

              
12345678

            
#include <stdio.h>

int main() 
{
    int variable;
    printf("%p\n", &variable);
    return 0;
}

A variable of pointer type is used to store the address, which is returned by the & operator.

To "unpack" the contents at the specified address, you must use the * operator on a variable of type pointer.

c

main

copy

              
12345678910

            
 #include <stdio.h>

int main()
{
    int variable = 1024;
    int* pVariable = &variable;
    printf("Address: %p\n", pVariable); // `%p` specifier for a pointer
    printf("Returned value by address: %d\n", *(pVariable)); // using `*` to pointer
    return 0;
}

Task

  1. Declare and initialize any variable with any value;
  2. Declare a pointer to the same data type as your variable;
  3. Assign the address of a variable to a pointer;
  4. Display an address of your variable;
  5. Display the value of the variable by the pointer.

Switch to desktop for real-world practiceContinue from where you are using one of the options below
Section 2. Chapter 1
Switch to desktop for real-world practiceContinue from where you are using one of the options below
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