Pointers to Structs
The C programming language allows you to create pointers not only to regular data types but also to structures (since a structure is a custom data type).
Declaration and initialization of a pointer looks like this:
struct <name_of_struct>
{
<field_of_struct>;
};
struct <name_of_struct>* <name_of_pointer>;
If <name_of_pointer> is a pointer to a structure,
then *(<name_of_pointer>) is the structure itself.
To access the fields of a structure through a pointer, you must use the -> operator.
-> is an analogue of the structure access operator .
main.c
12345678910111213141516171819202122#include <stdio.h> // structure declaration struct Point { int x; int y; }; int main() { // create a structure variable of Point type struct Point p1; p1.x = 10; p1.y = 20; // create a pointer to a structure of type Point and assign it the address of variable p1 struct Point* ptr = &p1; // Access structure members via pointer by `->` operator printf("Coordinates: (%d, %d)\n", ptr->x, ptr->y); return 0; }
Swipe to start coding
- Declare structure
Humanwhich contains two fieldsnameandage; - Initialize the structure
workerand fill the fields; - Declare and initialize a pointer
ptrto aworker; - Display information about the
worker.
Solution
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The C programming language allows you to create pointers not only to regular data types but also to structures (since a structure is a custom data type).
Declaration and initialization of a pointer looks like this:
struct <name_of_struct>
{
<field_of_struct>;
};
struct <name_of_struct>* <name_of_pointer>;
If <name_of_pointer> is a pointer to a structure,
then *(<name_of_pointer>) is the structure itself.
To access the fields of a structure through a pointer, you must use the -> operator.
-> is an analogue of the structure access operator .
main.c
12345678910111213141516171819202122#include <stdio.h> // structure declaration struct Point { int x; int y; }; int main() { // create a structure variable of Point type struct Point p1; p1.x = 10; p1.y = 20; // create a pointer to a structure of type Point and assign it the address of variable p1 struct Point* ptr = &p1; // Access structure members via pointer by `->` operator printf("Coordinates: (%d, %d)\n", ptr->x, ptr->y); return 0; }
Swipe to start coding
- Declare structure
Humanwhich contains two fieldsnameandage; - Initialize the structure
workerand fill the fields; - Declare and initialize a pointer
ptrto aworker; - Display information about the
worker.
Solution
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