Order of Statements
In our statistical analysis, we need to count the number of stations on each metro line and sort them in ascending order based on the number of stations.
This means we should first determine the number of stations for each metro line and then arrange them from the line with the fewest stations to the one with the most.
This information will help the construction company decide which metro lines should be prioritized for adding more stations.
For this, it's crucial to understand the sequence of SQL clauses, especially where to place the GROUP BY clause.
So, the order looks like this:
SELECTstatement;FROM table;WHEREclause;GROUP BYclause;ORDER BYclause;LIMITclause.
Let's consider an example of such statement order using our employee table. Suppose we need to retrieve the number of employees in each department whose salary is above 70000 and sort them from smallest to largest:
12345SELECT department, COUNT(employee_id) AS number_of_employees FROM employees WHERE salary > 70000 GROUP BY department ORDER BY number_of_employees
Swipe to start coding
Using the metro_travel_time table, find the number of stations (create a new column, named number_of_stations using station_name and COUNT() function) for each of the lines (line_name). Next, sort the result from smallest to largest.
Note
COUNT(column)is the function that counts the number of rows.
Brief Instructions
- Retrieve
line_nameand the count of rows in thestation_namecolumn. - Add the alias
number_of_stationsto the second column. - Group the data by
line_name. - Sort the result by
number_of_stations.
Solution
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Can you show me how to write a similar SQL query for the metro lines and stations?
Can you explain why the `GROUP BY` clause comes before `ORDER BY` in SQL?
Can you provide more examples of using `GROUP BY` and `ORDER BY` together?
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Order of Statements
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In our statistical analysis, we need to count the number of stations on each metro line and sort them in ascending order based on the number of stations.
This means we should first determine the number of stations for each metro line and then arrange them from the line with the fewest stations to the one with the most.
This information will help the construction company decide which metro lines should be prioritized for adding more stations.
For this, it's crucial to understand the sequence of SQL clauses, especially where to place the GROUP BY clause.
So, the order looks like this:
SELECTstatement;FROM table;WHEREclause;GROUP BYclause;ORDER BYclause;LIMITclause.
Let's consider an example of such statement order using our employee table. Suppose we need to retrieve the number of employees in each department whose salary is above 70000 and sort them from smallest to largest:
12345SELECT department, COUNT(employee_id) AS number_of_employees FROM employees WHERE salary > 70000 GROUP BY department ORDER BY number_of_employees
Swipe to start coding
Using the metro_travel_time table, find the number of stations (create a new column, named number_of_stations using station_name and COUNT() function) for each of the lines (line_name). Next, sort the result from smallest to largest.
Note
COUNT(column)is the function that counts the number of rows.
Brief Instructions
- Retrieve
line_nameand the count of rows in thestation_namecolumn. - Add the alias
number_of_stationsto the second column. - Group the data by
line_name. - Sort the result by
number_of_stations.
Solution
Thanks for your feedback!
single