Course Content
Introduction to C++
Introduction to C++
Manipulations with Arrays
You can also use for loops in arrays to find the sum of all elements:
int numbers[4] = {42, 12, 56, 98}; int sum = 0; for (int i = 0; i <= 3; i++) { sum += numbers[i]; } cout << sum;
Here the variable sum will store the sum of all elements, initially, it’s equal to 0. Then we iterate through the array using for loops and add each element to the variable sum.
You can also store in arrays the data from the user:
int numbers[4]; int sum = 0; for (int i = 0; i <= 3; i++) { cout << "Type the number: "; cin >> numbers[i]; sum += numbers[i]; }
Task
Find the multiplication of 10 elements printed by the user. Store the result in the variable mul
. Pay attention that the initial value of the variable mul
is 1
, since multiplication by 1 does not affect the result.
- Take input from the user.
- Multiply the user's number and the variable
mul
. Store the result in the variablemul
. - Print the variable
mul
.
Please, don’t forget to type the semicolon ;
at the end of the lines.
Thanks for your feedback!
Manipulations with Arrays
You can also use for loops in arrays to find the sum of all elements:
int numbers[4] = {42, 12, 56, 98}; int sum = 0; for (int i = 0; i <= 3; i++) { sum += numbers[i]; } cout << sum;
Here the variable sum will store the sum of all elements, initially, it’s equal to 0. Then we iterate through the array using for loops and add each element to the variable sum.
You can also store in arrays the data from the user:
int numbers[4]; int sum = 0; for (int i = 0; i <= 3; i++) { cout << "Type the number: "; cin >> numbers[i]; sum += numbers[i]; }
Task
Find the multiplication of 10 elements printed by the user. Store the result in the variable mul
. Pay attention that the initial value of the variable mul
is 1
, since multiplication by 1 does not affect the result.
- Take input from the user.
- Multiply the user's number and the variable
mul
. Store the result in the variablemul
. - Print the variable
mul
.
Please, don’t forget to type the semicolon ;
at the end of the lines.
Thanks for your feedback!
Manipulations with Arrays
You can also use for loops in arrays to find the sum of all elements:
int numbers[4] = {42, 12, 56, 98}; int sum = 0; for (int i = 0; i <= 3; i++) { sum += numbers[i]; } cout << sum;
Here the variable sum will store the sum of all elements, initially, it’s equal to 0. Then we iterate through the array using for loops and add each element to the variable sum.
You can also store in arrays the data from the user:
int numbers[4]; int sum = 0; for (int i = 0; i <= 3; i++) { cout << "Type the number: "; cin >> numbers[i]; sum += numbers[i]; }
Task
Find the multiplication of 10 elements printed by the user. Store the result in the variable mul
. Pay attention that the initial value of the variable mul
is 1
, since multiplication by 1 does not affect the result.
- Take input from the user.
- Multiply the user's number and the variable
mul
. Store the result in the variablemul
. - Print the variable
mul
.
Please, don’t forget to type the semicolon ;
at the end of the lines.
Thanks for your feedback!
You can also use for loops in arrays to find the sum of all elements:
int numbers[4] = {42, 12, 56, 98}; int sum = 0; for (int i = 0; i <= 3; i++) { sum += numbers[i]; } cout << sum;
Here the variable sum will store the sum of all elements, initially, it’s equal to 0. Then we iterate through the array using for loops and add each element to the variable sum.
You can also store in arrays the data from the user:
int numbers[4]; int sum = 0; for (int i = 0; i <= 3; i++) { cout << "Type the number: "; cin >> numbers[i]; sum += numbers[i]; }
Task
Find the multiplication of 10 elements printed by the user. Store the result in the variable mul
. Pay attention that the initial value of the variable mul
is 1
, since multiplication by 1 does not affect the result.
- Take input from the user.
- Multiply the user's number and the variable
mul
. Store the result in the variablemul
. - Print the variable
mul
.
Please, don’t forget to type the semicolon ;
at the end of the lines.