Decipher Binary Number

Task

So far, so good 😃 Convert binary code to the decimal one. Fill the gaps and follow the algorithm. The result of your manipulations is a specific number in math .

Create variable decimal_number for storing converted decimal number and assign 0 to it.
Print the binary number.
Define the variable power and assign 0 to it.
Define the loop that executes till the binary number is 0.
Count the remainder of division binary_number by 10 and assign it to the variable last_digit.
Multiply last_digit by the 2 raised to the relevant power.
Add the result to the decimal_number.
Decrease binary_number using integer division by 10.
Increase power by 1.
Print the decimal number.

Task

So far, so good 😃 Convert binary code to the decimal one. Fill the gaps and follow the algorithm. The result of your manipulations is a specific number in math .

Create variable decimal_number for storing converted decimal number and assign 0 to it.
Print the binary number.
Define the variable power and assign 0 to it.
Define the loop that executes till the binary number is 0.
Count the remainder of division binary_number by 10 and assign it to the variable last_digit.
Multiply last_digit by the 2 raised to the relevant power.
Add the result to the decimal_number.
Decrease binary_number using integer division by 10.
Increase power by 1.
Print the decimal number.

Note
You received one of the Armstrong number: the sum of the cubes of its own digits, let me explain this: 370 = 3^3 + 7^3 + 0^3 = 27 + 343 + 0 = 370

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Section 1. Chapter 3

Decipher Binary Number

Task

So far, so good 😃 Convert binary code to the decimal one. Fill the gaps and follow the algorithm. The result of your manipulations is a specific number in math .

Create variable decimal_number for storing converted decimal number and assign 0 to it.
Print the binary number.
Define the variable power and assign 0 to it.
Define the loop that executes till the binary number is 0.
Count the remainder of division binary_number by 10 and assign it to the variable last_digit.
Multiply last_digit by the 2 raised to the relevant power.
Add the result to the decimal_number.
Decrease binary_number using integer division by 10.
Increase power by 1.
Print the decimal number.

Task

So far, so good 😃 Convert binary code to the decimal one. Fill the gaps and follow the algorithm. The result of your manipulations is a specific number in math .

Create variable decimal_number for storing converted decimal number and assign 0 to it.
Print the binary number.
Define the variable power and assign 0 to it.
Define the loop that executes till the binary number is 0.
Count the remainder of division binary_number by 10 and assign it to the variable last_digit.
Multiply last_digit by the 2 raised to the relevant power.
Add the result to the decimal_number.
Decrease binary_number using integer division by 10.
Increase power by 1.
Print the decimal number.

Note
You received one of the Armstrong number: the sum of the cubes of its own digits, let me explain this: 370 = 3^3 + 7^3 + 0^3 = 27 + 343 + 0 = 370

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Section 1. Chapter 3

Decipher Binary Number

Task

So far, so good 😃 Convert binary code to the decimal one. Fill the gaps and follow the algorithm. The result of your manipulations is a specific number in math .

Create variable decimal_number for storing converted decimal number and assign 0 to it.
Print the binary number.
Define the variable power and assign 0 to it.
Define the loop that executes till the binary number is 0.
Count the remainder of division binary_number by 10 and assign it to the variable last_digit.
Multiply last_digit by the 2 raised to the relevant power.
Add the result to the decimal_number.
Decrease binary_number using integer division by 10.
Increase power by 1.
Print the decimal number.

Task

So far, so good 😃 Convert binary code to the decimal one. Fill the gaps and follow the algorithm. The result of your manipulations is a specific number in math .

Create variable decimal_number for storing converted decimal number and assign 0 to it.
Print the binary number.
Define the variable power and assign 0 to it.
Define the loop that executes till the binary number is 0.
Count the remainder of division binary_number by 10 and assign it to the variable last_digit.
Multiply last_digit by the 2 raised to the relevant power.
Add the result to the decimal_number.
Decrease binary_number using integer division by 10.
Increase power by 1.
Print the decimal number.

Note
You received one of the Armstrong number: the sum of the cubes of its own digits, let me explain this: 370 = 3^3 + 7^3 + 0^3 = 27 + 343 + 0 = 370

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Everything was clear?

Task

So far, so good 😃 Convert binary code to the decimal one. Fill the gaps and follow the algorithm. The result of your manipulations is a specific number in math .

Create variable decimal_number for storing converted decimal number and assign 0 to it.
Print the binary number.
Define the variable power and assign 0 to it.
Define the loop that executes till the binary number is 0.
Count the remainder of division binary_number by 10 and assign it to the variable last_digit.
Multiply last_digit by the 2 raised to the relevant power.
Add the result to the decimal_number.
Decrease binary_number using integer division by 10.
Increase power by 1.
Print the decimal number.

Note
You received one of the Armstrong number: the sum of the cubes of its own digits, let me explain this: 370 = 3^3 + 7^3 + 0^3 = 27 + 343 + 0 = 370

Switch to desktop for real-world practiceContinue from where you are using one of the options below

Section 1. Chapter 3

Switch to desktop for real-world practiceContinue from where you are using one of the options below