Dictionary Comprehensions
Dictionary comprehensions provide a concise way to create dictionaries in Python, similar to list comprehensions. They enable you to transform data into key-value pairs in a single line of code.
At its heart, a basic dictionary comprehension lets you construct a new dictionary by applying an expression to each key-value pair in an iterable variable.
{key_expression: value_expression for item in iterable}
key_expression: defines the key for each key-value pair;value_expression: defines the value corresponding to the key;iterable: the source of items to be processed (e.g., a list, range, or another iterable).
12345678910111213141516travel_wishlist = [ ['Paris', 2000], ['Tokyo', 3000], ['New York', 2500], ['Kyoto', 1500], ['Sydney', 4000] ] # Initialize an empty dictionary travel_budget = {} # Populate the dictionary using a for loop for destination, cost in travel_wishlist: travel_budget[destination] = cost print(travel_budget)
This code iterates through the travel_wishlist list, where each sublist contains a destination and its budget. The for loop assigns the destination as the key and the budget as the value in the travel_budget dictionary.
123456789101112travel_wishlist = [ ['Paris', 2000], ['Tokyo', 3000], ['New York', 2500], ['Kyoto', 1500], ['Sydney', 4000] ] # Create the dictionary using dictionary comprehension travel_budget = {destination: cost for destination, cost in travel_wishlist} print(travel_budget)
This example uses dictionary comprehension to achieve the same result as the previous example. Each destination becomes a key, and its corresponding cost becomes the value in the travel_budget dictionary, all in a single line.
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A traveler wants to organize their travel_wishlist by mapping each city name to its corresponding country. To achieve this efficiently, you need to transform the data into a dictionary.
- Extract city names and their corresponding countries from
travel_wishlist. - Store the resulting dictionary in
city_to_country.
Solution
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Dictionary comprehensions provide a concise way to create dictionaries in Python, similar to list comprehensions. They enable you to transform data into key-value pairs in a single line of code.
At its heart, a basic dictionary comprehension lets you construct a new dictionary by applying an expression to each key-value pair in an iterable variable.
{key_expression: value_expression for item in iterable}
key_expression: defines the key for each key-value pair;value_expression: defines the value corresponding to the key;iterable: the source of items to be processed (e.g., a list, range, or another iterable).
12345678910111213141516travel_wishlist = [ ['Paris', 2000], ['Tokyo', 3000], ['New York', 2500], ['Kyoto', 1500], ['Sydney', 4000] ] # Initialize an empty dictionary travel_budget = {} # Populate the dictionary using a for loop for destination, cost in travel_wishlist: travel_budget[destination] = cost print(travel_budget)
This code iterates through the travel_wishlist list, where each sublist contains a destination and its budget. The for loop assigns the destination as the key and the budget as the value in the travel_budget dictionary.
123456789101112travel_wishlist = [ ['Paris', 2000], ['Tokyo', 3000], ['New York', 2500], ['Kyoto', 1500], ['Sydney', 4000] ] # Create the dictionary using dictionary comprehension travel_budget = {destination: cost for destination, cost in travel_wishlist} print(travel_budget)
This example uses dictionary comprehension to achieve the same result as the previous example. Each destination becomes a key, and its corresponding cost becomes the value in the travel_budget dictionary, all in a single line.
Swipe to start coding
A traveler wants to organize their travel_wishlist by mapping each city name to its corresponding country. To achieve this efficiently, you need to transform the data into a dictionary.
- Extract city names and their corresponding countries from
travel_wishlist. - Store the resulting dictionary in
city_to_country.
Solution
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Completion rate improved to 5single
